scala play 2.1.1 json函数语法将数据映射为不同格式
我正在尝试使用函数语法编写一个自定义json序列化程序,但似乎找不到解决这个特定问题的正确方法。我有几个joda DateTime对象,我想用特定的格式为使用它的UI编写它们。谁能告诉我哪里出了问题 这是我目前正在处理的案例类,没有什么特别的事情发生scala play 2.1.1 json函数语法将数据映射为不同格式,json,scala,playframework,functional-programming,playframework-2.1,Json,Scala,Playframework,Functional Programming,Playframework 2.1,我正在尝试使用函数语法编写一个自定义json序列化程序,但似乎找不到解决这个特定问题的正确方法。我有几个joda DateTime对象,我想用特定的格式为使用它的UI编写它们。谁能告诉我哪里出了问题 这是我目前正在处理的案例类,没有什么特别的事情发生 case class Banner( id: Int = 0, ownerId: Int = 0, licenseeId: Option[Int] = None, statusColor: Option[String] = None
case class Banner(
id: Int = 0,
ownerId: Int = 0,
licenseeId: Option[Int] = None,
statusColor: Option[String] = None,
content: Option[String] = None,
displayStart: DateTime = new DateTime(),
displayEnd: DateTime = new DateTime(),
created: DateTime = new DateTime(),
updated: DateTime = new DateTime()
)
这些是我对序列化程序对象的导入
import play.api.libs.json._
import play.api.libs.functional.syntax._
import org.joda.time.DateTime
import org.joda.time.format.DateTimeFormat
首先,joda DateTime隐式地转换为long just fine,这样宏扩展器就可以很好地工作了,如果这就是我想要的
object MySerializers {
implicit val writesBanner = Json.writes[Banner]
}
我需要的是将displayStart和displayEnd对象转换为特定的字符串格式,而不是长值。这就是我试图做的
object MySerializers {
val userDateFormatter = DateTimeFormat.forPattern("MM/dd/yyyy HH:mm a")
implicit val writesBanner = (
(__ \ "id").write[Int] and
(__ \ "ownerId").write[Int] and
(__ \ "licenseeId").write[Int] and
(__ \ "statusColor").writeNullable[String] and
(__ \ "content").writeNullable[String] and
(__ \ "displayStart").write[DateTime].inmap[String](dt => userDateFormatter.print(dt)) and
(__ \ "displayEnd").write[DateTime].inmap[String](dt => userDateFormatter.print(dt)) and
(__ \ "created").write[DateTime] and
(__ \ "updated").write[DateTime]
)(unlift(Banner.unapply))
}
但是编译器对此并不满意,所以我似乎不理解使用inmap函数的正确方法
could not find implicit value for parameter fu:
play.api.libs.functional.InvariantFunctor[play.api.libs.json.OWrites]
[error] (__ \ "displayStart").write[DateTime].inmap[String](dt =>
userDateFormatter.print(dt)) and
[error] ^
非常感谢任何建议。我设法弄明白了这一点,我使用了错误类型的函子映射操作,并且使用了向后处理的类型。下面是使用更好的函数语法的工作读/写实现
implicit val writesBanner = (
(__ \ "id").write[Int] and
(__ \ "ownerId").write[Int] and
(__ \ "licenseeId").writeNullable[Int] and
(__ \ "statusColor").writeNullable[String] and
(__ \ "content").writeNullable[String] and
(__ \ "displayStart").write[String].contramap[DateTime](dt => userDateFormatter.print(dt)) and
(__ \ "displayEnd").write[String].contramap[DateTime](dt => userDateFormatter.print(dt)) and
(__ \ "created").write[DateTime] and
(__ \ "updated").write[DateTime]
)(unlift(Banner.unapply))
implicit val readsBanner = (
(__ \ "id").read[Int] and
(__ \ "ownerId").read[Int] and
(__ \ "licenseeId").readNullable[Int] and
(__ \ "statusColor").readNullable[String] and
(__ \ "content").readNullable[String] and
(__ \ "displayStart").read[String].fmap[DateTime](dt => DateTime.parse(dt, userDateFormatter)) and
(__ \ "displayEnd").read[String].fmap[DateTime](dt => DateTime.parse(dt, userDateFormatter)) and
(__ \ "created").read[DateTime] and
(__ \ "updated").read[DateTime]
)(Banner)
我绝对不是这方面的专家,但我很确定你使用inmap的方式是你如何使用contramap/fmap的组合 即:
implicit val formatBanner = (
<truncated>
(__ \ "displayStart").format[String].inmap(DateTime.parse(_, userDateFormatter), userDateFormatter.print(_)) and
<truncated>
)(Banner.apply, unlift(Banner.unapply))
implicit val formatBanner=(
(uu \“displayStart”).format[String].inmap(DateTime.parse(uuu,userDateFormatter)、userDateFormatter.print(uu))和
)(Banner.apply,unlift(Banner.unapply))