Python：解析json列表

大家好，我基本上想解析这个json数据

[
    {
        "id": 417862,
        "name": "octokit.rb",
        "full_name": "octokit/octokit.rb",
        "owner": {
            "login": "octokit",
            "id": 3430433,
            "avatar_url": "https://avatars0.githubusercontent.com/u/3430433?v=4",
            "gravatar_id": "",
            "url": "https://api.github.com/users/octokit",
            "html_url": "https://github.com/octokit",
            "followers_url": "https://api.github.com/users/octokit/followers",
            "following_url": "https://api.github.com/users/octokit/following{/other_user}",
            "gists_url": "https://api.github.com/users/octokit/gists{/gist_id}",
            "starred_url": "https://api.github.com/users/octokit/starred{/owner}{/repo}",
            "subscriptions_url": 
        } ]

我的问题是如何从json获取

“id”：417862

的值

谢谢。

那么：

mylist = [{
  "id": 417862,
  "name": "octokit.rb",
  "full_name": "octokit/octokit.rb",
  "owner": {
    "login": "octokit",
    "id": 3430433,
    "avatar_url": "https://avatars0.githubusercontent.com/u/3430433?v=4",
    "gravatar_id": "",
    "url": "https://api.github.com/users/octokit",
    "html_url": "https://github.com/octokit",
    "followers_url": "https://api.github.com/users/octokit/followers",
    "following_url": "https://api.github.com/users/octokit/following{/other_user}",
    "gists_url": "https://api.github.com/users/octokit/gists{/gist_id}",
    "starred_url": "https://api.github.com/users/octokit/starred{/owner}{/repo}",
    "subscriptions_url": "cats"
  }
}]

print mylist[0]['id']

---

这将返回打印

mylist

的第0个（即第一个）成员的

id

属性，该属性等于

417862

，假设您正在使用熊猫： 生成一个函数并返回列表的第一个值

def get_json_data(mylist):
    return mylist[0]

创建新列mn并应用该函数

df['new_col']=df.apply(lambda df: get_json_data(df['old_col']),axis=1)

---

一旦你拿到了gata，就把它正常化

pd.io.json.json_normalize(df['new_col'])

---

---

希望这有帮助：）

你在使用什么编程语言/库？我在使用python！！可能重复的