Json 颤振/飞镖
我对颤振和Dart都是新手,如果可以的话,我会尝试将一些android studio应用程序转换为使用颤振。我正在尝试解析一些简单的json,以了解所有dart/FLUTER特性如何帮助我 我要写入的类结构是:Json 颤振/飞镖,json,flutter,dart,serialization,Json,Flutter,Dart,Serialization,我对颤振和Dart都是新手,如果可以的话,我会尝试将一些android studio应用程序转换为使用颤振。我正在尝试解析一些简单的json,以了解所有dart/FLUTER特性如何帮助我 我要写入的类结构是: class Company extends Salinas { final String name; Company({this.name}) : super(); factory Company.fromJson(Map<String, dynamic> js
class Company extends Salinas {
final String name;
Company({this.name}) : super();
factory Company.fromJson(Map<String, dynamic> json) => _$CompanyFromJson(json);
Map<String, dynamic> toJson() => _$CompanyToJson(this);
}
class Salinas {
final int id;
Salinas({this.id});
factory Salinas.fromJson(Map<String, dynamic> json) => _$SalinasFromJson(json);
Map<String, dynamic> toJson() => _$SalinasToJson(this);
}
以及:
当我查看Company.g.dart文件时,是否没有对扩展类Salinas的引用?
有办法做到这一点吗
我显然遗漏了一些东西。您需要在子构造函数中定义扩展类属性,如下所示:
class Company extends Salinas {
final String name;
Company({id, this.name}) : super(id: id);
}
在您看到此结果后:
print(company.id) is 1
print(company.name) is Acme;
然后你就可以自由打印了
print(company.id);
print(company.name);
如果答案有帮助,您可以向上投票:)
print(company.id) is 1
print(company.name) is Acme;
class Company {
int id;
String name;
Company({this.id, this.name});
Company.fromJson(Map<String, dynamic> json) {
id = json['id'];
name = json['name'];
}
Map<String, dynamic> toJson() {
final Map<String, dynamic> data = new Map<String, dynamic>();
data['id'] = this.id;
data['name'] = this.name;
return data;
}
}
Company company = Company.fromJson(response);
print(company.id);
print(company.name);