json解析器的Apache Spark对象不可序列化异常

json解析器的Apache Spark对象不可序列化异常,json,scala,apache-spark,spark-streaming,lift,Json,Scala,Apache Spark,Spark Streaming,Lift,我正在从kafka队列读取数据[json as String],并使用liftweb json api将json作为字符串解析到case类中 下面是代码片段 val sparkStreamingContext = new StreamingContext(sparkConf, Seconds(5)) val kafkaParam: Map[String, String] = Map( "bootstrap.servers" -> kafkaServer,

我正在从kafka队列读取数据[json as String],并使用liftweb json api将json作为字符串解析到case类中

下面是代码片段

val sparkStreamingContext = new StreamingContext(sparkConf, Seconds(5))

    val kafkaParam: Map[String, String] = Map(
      "bootstrap.servers" -> kafkaServer,
      "key.deserializer" -> classOf[StringDeserializer].getCanonicalName,
      "value.deserializer" -> classOf[StringDeserializer].getCanonicalName,
      "zookeeper.connect" -> zookeeperUrl,
      "group.id" -> "demo-group")

    import org.apache.spark.streaming.kafka._
    import net.liftweb.json.{DefaultFormats, Formats}
    import net.liftweb.json._
    val topicSet = Map(kafkaTopic -> 1)
    val streaming = KafkaUtils.createStream[String, String, StringDecoder, StringDecoder](sparkStreamingContext, kafkaParam, topicSet, StorageLevel.MEMORY_AND_DISK)

    streaming.map { case (id, tweet) => implicit val formats: Formats = DefaultFormats
      (id, parse(tweet).extract[Tweet])
    }.print()

    sparkStreamingContext.start()
    sparkStreamingContext.awaitTermination()
我得到了这个例外

Exception in thread "main" org.apache.spark.SparkException: Job aborted due to stage failure: Task 0.0 in stage 1.0 (TID 1) had a not serializable result: net.liftweb.json.DefaultFormats$
Serialization stack:
    - object not serializable (class: net.liftweb.json.DefaultFormats$, value: net.liftweb.json.DefaultFormats$@74a2fec)
    - field (class: Tweet, name: formats, type: interface net.liftweb.json.Formats)
    - object (class Tweet, Tweet(Akash24,Adele))
    - field (class: scala.Tuple2, name: _2, type: class java.lang.Object)
    - object (class scala.Tuple2, (1,Tweet(Akash24,Adele)))
    - element of array (index: 0)
    - array (class [Lscala.Tuple2;, size 11)
有人能帮我解决这个问题吗 任何帮助都将不胜感激
从日志中可以看出,它看起来像是不可序列化类的一个简单异常。要更正,请使用以下代码:

sparkConf.registerKryoClasses(Array(classOf[DefaultFormats]))

val sparkStreamingContext = new StreamingContext(sparkConf, Seconds(5))

val kafkaParam: Map[String, String] = Map(
  "bootstrap.servers" -> kafkaServer,
  "key.deserializer" -> classOf[StringDeserializer].getCanonicalName,
  "value.deserializer" -> classOf[StringDeserializer].getCanonicalName,
  "zookeeper.connect" -> zookeeperUrl,
  "group.id" -> "demo-group")

import org.apache.spark.streaming.kafka._
import net.liftweb.json.{DefaultFormats, Formats}
import net.liftweb.json._
val topicSet = Map(kafkaTopic -> 1)
val streaming = KafkaUtils.createStream[String, String, StringDecoder, StringDecoder](sparkStreamingContext, kafkaParam, topicSet, StorageLevel.MEMORY_AND_DISK)

streaming.map { case (id, tweet) => implicit val formats: Formats = DefaultFormats
  (id, parse(tweet).extract[Tweet])
}.print()

sparkStreamingContext.start()
sparkStreamingContext.awaitTermination()

它将使
DefaultFormats
类可序列化,Spark master将能够向所有工作节点发送
隐式val格式

是否可以包含
Tweet
定义?@zero323案例类Tweet(用户:字符串,Tweet:String)