不将json转换为表

我试图将下面的json对象转换为一个表，但Corona没有这样做，所以打印结果为0。我试着用“”替换“\uuuu type”：“Object”，以避免混淆，但没有运气

   tempTable1 = '{"result":[{"__type":"Object","address":"95-97 Whitehorse Rd Blackburn VIC 3130","className":"allJobs","content":"Dr test","coord":{"__type":"GeoPoint","latitude":-37.817272,"longitude":145.149913},"createdAt":"2015-05-21T05:15:45.012Z","done":false,"email":"na","job":"psychologist","objectId":"PfKJkmIQKw","order":1,"phone":"0422031410","postcode":"3130","suburb":"Blackburn VIC","updatedAt":"2015-05-27T08:15:46.607Z","web":"na"},{"__type":"Object","address":"Suite 9 10-12 Prospect St Box Hill ","className":"allJobs","content":"Dr 2)","coord":{"__type":"GeoPoint","latitude":-37.817957,"longitude":145.118997},"createdAt":"2015-05-21T05:17:56.382Z","done":false,"email":"soboodi@yahoo.com","job":"lawyer","objectId":"xnLABEm5S4","order":1,"phone":"03 9890 0797","postcode":"3128","suburb":"Box Hill VIC","updatedAt":"2015-05-27T08:15:21.112Z","web":"na"}]}'


 local tables  = json.decode(tempTable1)
 print(#tables) 

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我把结果说错了。因为它正在其他表中创建一些表。下面是正确的

print (event.response.result[5].email)
print (event.response.result[5].coord.latitude)