JQ在JSON中对整数值进行排序

我有一堆JSON对象，如下所示：

{"AccountID":"290859614811","number_of_requests":"59944"}
{"AccountID":"421258792169","number_of_requests":"3132"}
{"AccountID":"433594311540","number_of_requests":"1541"}
{"AccountID":"406912498377","number_of_requests":"678"}
{"AccountID":"850981987534","number_of_requests":"558"}
{"AccountID":"763725063017","number_of_requests":"470"}
{"AccountID":"notaccount","number_of_requests":"8"}
....

我试图根据请求的数量按升序对它们进行排序

但当我运行以下程序时：

jq-S'.results[]| map（{（.field）：.value}）|添加'FILENAME | jq-S-c'排序依据（.u请求数）[]'

我的结局是：

{"AccountID":"433594311540","number_of_requests":"1541"}
{"AccountID":"421258792169","number_of_requests":"3132"}
{"AccountID":"763725063017","number_of_requests":"470"}
{"AccountID":"850981987534","number_of_requests":"558"}
{"AccountID":"290859614811","number_of_requests":"59944"}
{"AccountID":"406912498377","number_of_requests":"678"}
{"AccountID":"notaccount","number_of_requests":"8"}
...

---

基本上，sort_by函数将“558”/“59944”视为小于“8”、“6”等。是否有办法解决此问题？

您需要将值转换为数字，使用

tonumber

：

jq -s -c 'sort_by(.number_of_requests|tonumber)'

---

您需要使用

tonumber

将值转换为数字：

jq -s -c 'sort_by(.number_of_requests|tonumber)'