不能';使用kotlin通道无法接收少量消息
我有下面的kotlin合作程序代码不能';使用kotlin通道无法接收少量消息,kotlin,kotlinx.coroutines,Kotlin,Kotlinx.coroutines,我有下面的kotlin合作程序代码 import kotlinx.coroutines.* import kotlinx.coroutines.channels.* fun main() = runBlocking { val channel = Channel<Int>() val job = launch { for(x in 1..5) { println("s
import kotlinx.coroutines.*
import kotlinx.coroutines.channels.*
fun main() = runBlocking {
val channel = Channel<Int>()
val job = launch {
for(x in 1..5) {
println("sending $x")
channel.send(x)
}
channel.close()
}
for (y in channel) {
// if (!channel.isClosedForReceive && !channel.isClosedForSend)
println( "received ${channel.receive()} isClosedForSend ${channel.isClosedForSend} isClosedForReceive ${channel.isClosedForReceive} " )
}
job.join()
}
如果(!channel.isClosedForReceive&&!channel.isClosedForSend)不注释行,则会得到相同的输出,但有例外
sending 1
sending 2
received 2 isClosedForSend false isClosedForReceive false
sending 3
sending 4
received 4 isClosedForSend false isClosedForReceive false
sending 5
Exception in thread "main" kotlinx.coroutines.channels.ClosedReceiveChannelException: Channel was closed
at kotlinx.coroutines.channels.Closed.getReceiveException(AbstractChannel.kt:1081)
at kotlinx.coroutines.channels.AbstractChannel.receiveResult(AbstractChannel.kt:577)
at kotlinx.coroutines.channels.AbstractChannel.receive(AbstractChannel.kt:570)
如何才能毫无例外地获得正确的输出?您只需编写
for (y in channel) {
println(y)
}
你可以直接写
for (y in channel) {
println(y)
}