Laravel 5 如何在laravel中传递url中的三个变量

路由：：get（'reports/{reports}/leave'，['as'=>'reports.leave'，'uses'=>'ReportController@leave']);

@foreach（$dat作为$report）

{！！$report->name！！}

要传递三个变量，可以尝试以下示例代码：

路线：

Route::get('admin/{variable_1}/reports/{variable_2}/leave/{variable_3}', 'ReportController@leave');

控制器方法：

public function leave($variable_1, $variable_2, $variable_3){

}

HTML（刀片）链接：

尝试下面给定的代码：
路线

Route::get('reports/{reports}/leave/{date}/{fdate}', [
'as'=> 'reportsLeave', 'uses' =>'ReportController@leave']);

@foreach($dat as $report)
<?php 
    $date=$_POST['date']; 
    $fdate=$_POST['fdate'];
    ?><td><a href="{{ URL::route('reportsLeave',[$reports => $report->name, 'date' => $date, 'fdate' => $fdate) }}">{!!$report->name!!}</td>

刀片

Route::get('reports/{reports}/leave/{date}/{fdate}', [
'as'=> 'reportsLeave', 'uses' =>'ReportController@leave']);

@foreach($dat as $report)
<?php 
    $date=$_POST['date']; 
    $fdate=$_POST['fdate'];
    ?><td><a href="{{ URL::route('reportsLeave',[$reports => $report->name, 'date' => $date, 'fdate' => $fdate) }}">{!!$report->name!!}</td>

希望以上建议的方法对您有用。祝你好运

public function leave($reports, $date, $fdate){...}