Laravel雄辩的“have”和计算列

我的控制器中有以下逻辑，它在

having

语句中失败。如果没有

$type

步骤，数据将按预期显示（因此

addSelect

按预期工作）。如何使用计算列

meters\u count

过滤

have

错误：

SQLSTATE[42703]: Undefined column: 7 ERROR: column "meters_count" does not exist

守则：

// Get all customers visible to this user
$query = Site::with('customer.logo', 'mainContact', 'address')
    ->addSelect(['meters_count' => Meter::selectRaw('COUNT(*)')->whereColumn('meters.site_id', 'sites.id')]);

// Filter for user type
switch ($type) {

    case 'deleted':
        $query->onlyTrashed();
        break;

    case 'no_meters':
        $query->groupBy('sites.id')
           ->having('meters_count', '=', 0);
        break;

    default:
        $query->groupBy('sites.id')
           ->having('meters_count', '>', 0);
}

// Run query here...
$sites = $query-get();

---

在应用之前，需要应用GroupBy函数

$users = DB::table('users')
                ->groupBy('account_id')
                ->having('account_id', '>', 100)
                ->get();

我是这样做的：

// Get all customers visible to this user
$query = Site::with('customer.logo', 'mainContact', 'address')
    ->withCount('meters');

// Filter for user type
switch ($type) {

   case 'deleted':
        $query->onlyTrashed();
        break;

   case 'no_meters':
        $query->groupBy('sites.id')
            ->havingRaw('(SELECT COUNT(*) FROM meters WHERE meters.site_id = sites.id) = ?', [0]);
        break;

   default:
        $query->groupBy('sites.id')
            ->havingRaw('(SELECT COUNT(*) FROM meters WHERE meters.site_id = sites.id) > ?', [0]);
    }

}

// Run query here...
$sites = $query->get();