Laravel 拉维4查询

有可能以雄辩的口才来执行这样的事情吗

SELECT (SELECT `name` from `players` WHERE `player_id`=`id`) AS `name`, `value` FROM `player_skills` WHERE `skillid`=0

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这看起来只是一个简单的关系，所以您可以这样做：

PlayerSkill::with('Player')->where('skillid',0)->get();

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您可以这样简单地运行查询

DB::raw('SELECT (SELECT `name` from `players` WHERE `player_id`=`id`) AS `name`, `value` FROM `player_skills` WHERE `skillid`=0');

或

或

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祝你好运：）

在问这个问题之前，你有没有费心使用SO搜索或阅读文档@是的，我看到了，我没看到。谢谢pget自己熟悉文档中的基本、查询生成器和雄辩的ORM章节。它将帮助您更好地理解Laravel 4，并解决上面列出的其他问题。再加上，

DB::statement('SELECT (SELECT `name` from `players` WHERE `player_id`=`id`) AS `name`, `value` FROM `player_skills` WHERE `skillid`=0');

DB::select('SELECT (SELECT `name` from `players` WHERE `player_id` = ?) AS `name`, `value` FROM `player_skills` WHERE `skillid`= ?', array('id', 0));