Laravel:通过指定名称获取路由

Laravel:通过指定名称获取路由,laravel,get,routes,Laravel,Get,Routes,我有如下配置路径: Route::get( 'index/{type?}', [ 'as' => 'AAA.index', 'uses' => 'AAA@index', ] ); Route::any( 'create/{type}', [ 'as' => 'AAA.create', 'uses' => 'AAA@create', ] ); 如果我有

我有如下配置路径:

Route::get(
    'index/{type?}',
    [
        'as'   => 'AAA.index',
        'uses' => 'AAA@index',
    ]
);

Route::any(
    'create/{type}',
    [
        'as'   => 'AAA.create',
        'uses' => 'AAA@create',
    ]
);
如果我有一个字符串AAA.index,我想得到index/{type?}

如果我有一个字符串AAA.create,我想得到create/{type?}

什么方法可以做到这一点?

使用路由方法:

路由('AAA.index',$parameter)

请参见:

使用路线方法:

路由('AAA.index',$parameter)

见: