Laravel:通过指定名称获取路由
我有如下配置路径:Laravel:通过指定名称获取路由,laravel,get,routes,Laravel,Get,Routes,我有如下配置路径: Route::get( 'index/{type?}', [ 'as' => 'AAA.index', 'uses' => 'AAA@index', ] ); Route::any( 'create/{type}', [ 'as' => 'AAA.create', 'uses' => 'AAA@create', ] ); 如果我有
Route::get(
'index/{type?}',
[
'as' => 'AAA.index',
'uses' => 'AAA@index',
]
);
Route::any(
'create/{type}',
[
'as' => 'AAA.create',
'uses' => 'AAA@create',
]
);
如果我有一个字符串AAA.index,我想得到index/{type?}
如果我有一个字符串AAA.create,我想得到create/{type?}
什么方法可以做到这一点?使用路由方法:
路由('AAA.index',$parameter)
请参见:使用路线方法:
路由('AAA.index',$parameter)
见: