Laravel-错误“;传递给Lightning\Validation\Factory::make()的参数2必须是array类型,对象为“给定”;
这个代码怎么了Laravel-错误“;传递给Lightning\Validation\Factory::make()的参数2必须是array类型,对象为“给定”;,laravel,validation,Laravel,Validation,这个代码怎么了 class DeleteDetail extends FormRequest { public function authorize() { return true; } public function rules() { $request = Request::all(); $rules = [ 'hobby' => [ 'string',
class DeleteDetail extends FormRequest {
public function authorize() {
return true;
}
public function rules() {
$request = Request::all();
$rules = [
'hobby' => [
'string',
'between:3,20',
Rule::exists('user_hobby')->where(function ($query) use ($request) {
$query->where('hobby', $request['hobby'])->where('user_id', Auth::user()->id);
}),
],
];
return Validator::make($request, $rules);
}
}
我收到的错误:
传递给Illumination\Validation\Factory::make()的参数2必须是array类型,给定的对象如果从
规则
方法本身内部返回了错误的值,则应返回包含验证规则的数组
,而不是Validation::make
:
public function rules() {
...
return $rules;
}
rules
函数应返回包含规则的数组
public function rules() {
$request = Request::all();
$rules = [
'hobby' => [
'string',
'between:3,20',
Rule::exists('user_hobby')->where(function ($query) use ($request) {
$query->where('hobby', $request['hobby'])->where('user_id', Auth::user()->id);
}),
],
];
return $rules;
}
然后在控制器中:
public function store(DeleteDetail $request)
{
// the code in here has passed the validation..
}
您正在尝试创建请求验证类吗?谢谢您的帮助。