Linux 使用bash合并多个SQLite数据库？

我有多个具有相同模式的sqlite数据库，我想将它们合并在一起，因为我有一个唯一的列，并且可能存在重复的风险，我使用的是

插入或忽略

，在sqlite中很容易：

sqlite3 database.db3
sqlite> attach './db1.db3' as s1;
sqlite> attach './db2.db3' as s2;
sqlite> attach './db3.db3' as s3;
sqlite> insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s1.table;
sqlite> insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s2.table;
sqlite> insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s3.table;
sqlite> .exit

我读过关于dump的文章，但我不想合并整个模式，只合并一个表，所以我考虑了这个解决方案，现在一切正常，但我需要通过bash运行所有这些，我尝试了以下方法，但没有：

sqlite3 database.db3 "attach './db1.db3' as s1;"
sqlite3 database.db3 "attach './db2.db3' as s2;"
sqlite3 database.db3 "attach './db3.db3' as s3;"
sqlite3 database.db3 "select count(*) from s1.table;"
sqlite3 database.db3 "select count(*) from s2.table;"
sqlite3 database.db3 "select count(*) from s3.table;"

它说

错误：没有这样的表：s1.表

我做错了什么

使用如下所示的

sqlite3 database.db3 << "EOF"
attach './db1.db3' as s1;
attach './db2.db3' as s2;
attach './db3.db3' as s3;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s1.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s2.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s3.table;
.exit
EOF

sqlite3 database.db3使用如下所示的

sqlite3 database.db3 << "EOF"
attach './db1.db3' as s1;
attach './db2.db3' as s2;
attach './db3.db3' as s3;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s1.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s2.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s3.table;
.exit
EOF

sqlite3 database.db31）创建一个文本文件，其中包含要输入sqlite命令行程序的行，如下所示：

sqlite3 database.db3 < commandsFile

attach './db1.db3' as s1;
attach './db2.db3' as s2;
attach './db3.db3' as s3;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s1.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s2.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s3.table;
.exit

然后只需调用
sqlite3 database.db

2） 使用外壳

#!/bin/bash 

sqlite3 database.db <<"EOF"
attach './db1.db3' as s1;
attach './db2.db3' as s2;
attach './db3.db3' as s3;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s1.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s2.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s3.table;
.exit
EOF

#/bin/bash
sqlite3 database.db1）创建一个文本文件，其中包含要输入sqlite命令行程序的行，如下所示：

sqlite3 database.db3 < commandsFile

attach './db1.db3' as s1;
attach './db2.db3' as s2;
attach './db3.db3' as s3;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s1.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s2.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s3.table;
.exit

然后只需调用
sqlite3 database.db

2） 使用外壳

#!/bin/bash 

sqlite3 database.db <<"EOF"
attach './db1.db3' as s1;
attach './db2.db3' as s2;
attach './db3.db3' as s3;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s1.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s2.table;
insert or ignore into table (c1, c2, c3) select c1, c2, c3 from s3.table;
.exit
EOF

#/bin/bash
sqlite3数据库.db