Linux 如何读取.dat文件和grep特定值

我正在尝试使用bash脚本读取.dat文件

该值包含除第一列外大于0的文件大小。大于零值可以出现在任何行中

I have awk script to read line by line. 



 1349848860, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
1349848920, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
1349848980, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
1349849040, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
1349849100, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0
1349849160, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 227.736, 2, 0, 29378, 0, 0, 0, 0, 0
1349849220, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
1349849280, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
1349849340, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
1349851200, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
1349851260, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
1349851320, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0
1349851380, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 227.736, 2, 0, 29620, 0, 0, 0, 0, 0
1349851440, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
#!/bin/bash
FILENAME=$1

awk '{kount++;print  kount, $0}     END{print "\nTotal " kount " lines read"}' $FILENAME
awk '{print $13}' $FILENAME

期望输出-

   227.736, 2,  29378 
   227.736, 2,  29620

谢谢你的帮助。

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Naveen

据我所知，您希望对所有包含0或1以外的数字的行进行grep，而不计算行首的第一个数字。怎么样

egrep ',.*([2-9]|[0-9.]{4,})' tmp.txt

这将根据您的示例打印行

1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0 1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0 1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0 1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0 1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0 1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0

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如果要获取此文件中每行（基于您的输入）的第13列（即14353）、第16列（即450.03）和第19列（即69832）的内容，请尝试以下操作：

awk < test.dat -F ', ' '{print $13,$16,$19}'

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如果我了解您的需求：

awk -F"," '{for (i=2;i<=NF;i++){if ($i > 1) {print}}}' file.dat

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你的问题是什么？你在尝试grep什么值？这还不清楚。是否要在第一列之后检索任何正整数？请显示您的预期输出。对于不清楚的问题，请给出清晰的答案；）这个

644.982

值是从哪里来的？很抱歉，我搞砸了，因为…值经常变化…我急忙发布了这个问题，因为有紧急需求。非常抱歉。

awk -F"," '{for (i=2;i<=NF;i++){if ($i > 1) {print}}}' file.dat

1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0
1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0
1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0
1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0
1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0
1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0
1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0
1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0
1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0
1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0
1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0
1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0
1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0