Linux 如何仅存储curl命令的一个响应

我希望将curl命令的输出存储在一个变量中，而不是整个响应中，只存储该响应的一个值 我有这个卷曲命令

curl -H "Authorization: Bearer $TOKEN" -X POST -H "content-type:application/json" \
  -d '{
    "name":"'"$ORG_NAME"'",
    "displayName":"'"$ORG_DISPLAY_NAME"'",
    "description":"'"$ORGANIZATION_DESCRIPTION"'",
    "runtimeType":"'"$RUNTIMETYPE"'",
    "analyticsRegion":"'"$ANALYTICS_REGION"'"
  }' \
  "https://apigee.googleapis.com/v1/organizations?parent=projects/$PROJECT_ID"

当我点击这个命令时，它会显示如下的响应

{
  "name": "organizations/heloo/operations/keijfiejwfefekd",
  "metadata": {
    "@type": "type.googleapis.com/google.cloud.apigee.v1.OperationMetadata",
    "operationType": "INSERT",
    "targetResourceName": "organizations/heloo",
    "state": "IN_PROGRESS"
  }
}

所以在响应中，我想将这个状态值存储在一个变量中

test=$(curl -H "Authorization: Bearer $TOKEN" -X POST -H "content-type:application/json" \
  -d '{
    "name":"'"$ORG_NAME"'",
    "displayName":"'"$ORG_DISPLAY_NAME"'",
    "description":"'"$ORGANIZATION_DESCRIPTION"'",
    "runtimeType":"'"$RUNTIMETYPE"'",
    "analyticsRegion":"'"$ANALYTICS_REGION"'"
  }' \
  "https://apigee.googleapis.com/v1/organizations?parent=projects/$PROJECT_ID" | jq '.metadata.state')

---

它将起作用

参数扩展发生在双引号之间，而不是单引号之间。谢谢，它起作用了