Linux 如何创建正常运行的程序？因为我的程序一直在运行，不会停止

我的英语很差，但我正在努力解释我的问题。 我想在bash上创建一个小程序，用户必须在其中猜测数字。但我的计划没有尽头

我是bash脚本的新手，但我每天都在努力做得更好。 我用的是CentOS 7。我转到/usr/bin/local并创建一些文件，给他chmod+x并用gedit打开：

#!/usr/bin/bash

#This script should ask us our name and play the game "Guess the Number" with us.

echo "What is your name?"
read name
echo "Hello $name"
echo "I want to play $ name with you, you have to guess the number from 1 to 10)"
echo "Are you ready?"
read rdy


answer=$(( answer = $RANDOM % 10 ))


read -p "Enter your number: " variant 
     while [ $answer != $variant ]; do

if [ $answer -gt $variant ]; then 
     echo "Your number is bigger, try again"

elif [ $answer -lt $variant ]; then
     echo "Your number is smaller, try again"

  continue

fi

done

eternal "Your number is smaller/bigger"
until you press ctrl+c

我需要做什么，请帮忙。我知道非业余爱好者不喜欢新手，但我需要你的帮助，告诉我我的错误，我会变得更好。谢谢

你打电话吗

#!/bin/bash
echo "What is your name?"
read name
echo "Hello $name"
echo "I want to play  with you, you have to guess the number from 1 to 10"


answer=$(( $RANDOM % 10 ))

while true
do
    read -p "Enter your number: " variant
    if [ "$answer" -gt "$variant" ]; then
        echo "The number is bigger, try again"

    elif [ "$answer" -lt "$variant" ]; then
        echo "The number is smaller, try again"
    else
        break;
    fi

done
echo "Yes, the answer was ${answer}"

read -p "Enter your number: " variant

在

while

循环之前

在循环中，您永远不会更改

变量

，因此原始值将在

while

条件中重新使用。永远

---

您可以从

variant=-1

开始，将

read

移动到循环内，或执行类似@xiawi的操作。

read-p“输入您的号码：”variant while[$answer！=$variant]读取变量并在循环endlessy中检查它，而不是每次更改它。我猜你想读循环中的变量。另外，通过运行脚本并记住引用变量。非常感谢！我需要练习。谢谢