Linux 用于在每小时文件夹中移动日志文件的脚本
这是我的剧本：Linux 用于在每小时文件夹中移动日志文件的脚本,linux,bash,shell,unix,scripting,Linux,Bash,Shell,Unix,Scripting,这是我的剧本： set -x PTH=/data0101/track_logs cd /data0101/track_logs if [[ `ls -lrth | grep IMEI_TRACK | wc -l` -gt 0 ]]; then FILE_COUNT=`ls -lrth | grep IMEI_TRACK | wc -l` YEAR=`date | awk '{print $6}'` mkdir
set -x
PTH=/data0101/track_logs
cd /data0101/track_logs
if [[ `ls -lrth | grep IMEI_TRACK | wc -l` -gt 0 ]];
then
FILE_COUNT=`ls -lrth | grep IMEI_TRACK | wc -l`
YEAR=`date | awk '{print $6}'`
mkdir $PTH/$YEAR
MONTH=`date | awk '{print $2}'`
mkdir $PTH/$YEAR/$MONTH
DAY=`date | awk '{print $3}'`
HOUR=`date | awk '{print $4}' | cut -d":" -f 1`
if [[ $HOUR -ne 0 ]];
then
HR=$(( $HOUR - 1 ))
else
DAY=$(( $DAY - 1 ))
HR=23
mkdir $PTH/$YEAR/$MONTH/$DAY
fi
case $HR in
00-23) for (( i=1;i<=$FILE_COUNT;i++ ))
do
chk=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $8}' | cut -d: -f1`
FILE=`ls -lrth | grep IMEI_TRACK | awk '{print $9}'`
if [[ $chk -eq $HR ]];
then
mkdir $PTH/$YEAR/$MONTH/$DAY/$HR
mv $FILE $PTH/$YEAR/$MONTH/$DAY/$HR/
else
break
fi
done ;;
esac
fi
case $HR in
[00-23]) for (( i=1;i<=$FILE_COUNT;i++ ))
do
chk=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $8}' | cut -d: -f1`
FILE=`ls -lrth | grep IMEI_TRACK | awk '{print $9}'`
if [[ $chk -eq $HR ]];
then
mkdir $PTH/$YEAR/$MONTH/$DAY/$HR
mv $FILE $PTH/$YEAR/$MONTH/$DAY/$HR/
else
break
fi
done ;;
esac
#!/bin/bash
PTH="/data0101/track_logs"
cd "$PTH"
DIR=$(date +"%Y/%m/%d/%H")
mkdir "$DIR"
find ./ -mtime -1 -name "*IMEI_TRACK*" -type f -exec mv "{}" "$DIR" \;
案例中的$HR
[00-23]）对于（（i=1；i您需要分别检查每个数字，如[0-2][0-9]
，您还可以使用find
而不是在文件上循环，mkdir
和-p
选项来创建父目录（如有必要），并使用read
进行多变量赋值：
#!/bin/bash
PTH="/data0101/track_logs"
cd "$PTH"
if [[ $(ls -lrth | grep IMEI_TRACK | wc -l) -gt 0 ]]; then
DATE=$(date +"%Y %m %d %H")
DIR=${DATE// /\/}
read YEAR MONTH DAY HOUR <<<$DATE
case $HOUR in
[0-2][0-9]) mkdir -p "$DIR"
find ./ -mtime -1 -name "*IMEI_TRACK*" -type f -exec mv "{}" "$DIR" \;;;
esac
fi
您需要分别检查每个数字，例如[0-2][0-9]
，您还可以使用find
而不是在文件上循环，mkdir
使用-p
选项创建父目录（如果需要），以及使用read
进行多变量赋值：
#!/bin/bash
PTH="/data0101/track_logs"
cd "$PTH"
if [[ $(ls -lrth | grep IMEI_TRACK | wc -l) -gt 0 ]]; then
DATE=$(date +"%Y %m %d %H")
DIR=${DATE// /\/}
read YEAR MONTH DAY HOUR <<<$DATE
case $HOUR in
[0-2][0-9]) mkdir -p "$DIR"
find ./ -mtime -1 -name "*IMEI_TRACK*" -type f -exec mv "{}" "$DIR" \;;;
esac
fi
这是我最后的剧本：
cd /data0101/track_logs
if [[ `ls -lrth | grep IMEI_TRACK | wc -l` -gt 0 ]];
then
FILE_COUNT=`ls -lrth | grep IMEI_TRACK | wc -l`
YEAR=`date | awk '{print $6}'`
MONTH=`date | awk '{print $2}'`
DAY=`date | awk '{print $3}'`
HOUR=`date | awk '{print $4}' | cut -d":" -f 1`
if [[ "$HOUR" -ne 0 ]];
then
HR=$(( $HOUR - 1 ))
else
DAY=$(( $DAY - 1 ))
HR=23
fi
case $HR in
[0-9]) for (( i=1;i<=$FILE_COUNT;i++ ))
do
chk_hr=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $8}' | cut -d: -f1`
chk_day=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $7}'`
FILE=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $9}'`
if [[ $chk_hr -eq $HR && $chk_day -eq $DAY ]];
then
mkdir -p $DIR_PATH/$YEAR/$MONTH/$DAY/$HR
mv $FILE $DIR_PATH/$YEAR/$MONTH/$DAY/$HR/
fi
done ;;
[1-2][0-9]) for (( i=1;i<=$FILE_COUNT;i++ ))
do
chk_hr=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $8}' | cut -d: -f1`
chk_day=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $7}'`
FILE=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $9}'`
if [[ $chk_hr -eq $HR && $chk_day -eq $DAY ]];
then
mkdir -p $DIR_PATH/$YEAR/$MONTH/$DAY/$HR
mv $FILE $DIR_PATH/$YEAR/$MONTH/$DAY/$HR/
fi
done ;;
esac
fi
enter code here
cd/data0101/track\u日志
如果[`ls-lrth | grep IMEI|u TRACK | wc-l`-gt 0]；
然后
FILE|u COUNT=`ls-lrth | grep IMEI|u TRACK | wc-l`
年份=`date | awk'{print$6}'`
月份=`date | awk'{print$2}'`
DAY=`date | awk'{print$3}'`
HOUR=`date | awk'{print$4}'| cut-d:'-f 1`
如果[[“$HOUR”-ne 0]]；
然后
人力资源=$（$小时-1））
其他的
日=$（$日-1））
HR=23
fi
案例中的$HR
[0-9]）对于（（i=1；i这是我最后的脚本：
cd /data0101/track_logs
if [[ `ls -lrth | grep IMEI_TRACK | wc -l` -gt 0 ]];
then
FILE_COUNT=`ls -lrth | grep IMEI_TRACK | wc -l`
YEAR=`date | awk '{print $6}'`
MONTH=`date | awk '{print $2}'`
DAY=`date | awk '{print $3}'`
HOUR=`date | awk '{print $4}' | cut -d":" -f 1`
if [[ "$HOUR" -ne 0 ]];
then
HR=$(( $HOUR - 1 ))
else
DAY=$(( $DAY - 1 ))
HR=23
fi
case $HR in
[0-9]) for (( i=1;i<=$FILE_COUNT;i++ ))
do
chk_hr=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $8}' | cut -d: -f1`
chk_day=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $7}'`
FILE=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $9}'`
if [[ $chk_hr -eq $HR && $chk_day -eq $DAY ]];
then
mkdir -p $DIR_PATH/$YEAR/$MONTH/$DAY/$HR
mv $FILE $DIR_PATH/$YEAR/$MONTH/$DAY/$HR/
fi
done ;;
[1-2][0-9]) for (( i=1;i<=$FILE_COUNT;i++ ))
do
chk_hr=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $8}' | cut -d: -f1`
chk_day=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $7}'`
FILE=`ls -lrth | grep IMEI_TRACK | head -$i | tail -1 | awk '{print $9}'`
if [[ $chk_hr -eq $HR && $chk_day -eq $DAY ]];
then
mkdir -p $DIR_PATH/$YEAR/$MONTH/$DAY/$HR
mv $FILE $DIR_PATH/$YEAR/$MONTH/$DAY/$HR/
fi
done ;;
esac
fi
enter code here
cd/data0101/track\u日志
如果[`ls-lrth | grep IMEI|u TRACK | wc-l`-gt 0]；
然后
FILE|u COUNT=`ls-lrth | grep IMEI|u TRACK | wc-l`
年份=`date | awk'{print$6}'`
月份=`date | awk'{print$2}'`
DAY=`date | awk'{print$3}'`
HOUR=`date | awk'{print$4}'| cut-d:'-f 1`
如果[[“$HOUR”-ne 0]]；
然后
人力资源=$（$小时-1））
其他的
日=$（$日-1））
HR=23
fi
案例中的$HR
[0-9]）对于（（i=1；只检查一个HR值：这是00-23
。这不代表一个范围。有关提示，请参阅问题。只检查一个HR值：这是00-23
。这不代表一个范围。有关提示，请参阅问题。您可能还需要一个线性版本cd”/data0101/track_logs“&&mkdir-p$（日期）+“%Y/%m/%d/%H”）和&find./-mtime-1-name“*IMEI\u TRACK*”-type f-exec mv“{}”“$\
您可能还需要1行程序版本cd”/data0101/TRACK\u logs”和&mkdir-p$（date+“%Y/%m/%d/%H”）&和&find./-mtime-1-name“*IMEI\u TRACK*”-type f-exec mv“{