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List 具有可变输入数的Haskell发生器？

list haskell recursion

List 具有可变输入数的Haskell发生器？,list,haskell,recursion,List,Haskell,Recursion,目前，我的代码看起来有点像这样： gen (x:[]) = [[a] | a <- (someOp x)] gen (x:y:[]) = [[a,b] | a <- (someOp x), b <- (someOp y)] gen (x:y:z:[]) = [[a,b,c] | a <- (someOp x), b <- (someOp y), c <- (someOp z)] gen（x:[]）=[[a]| a您可以递归执行此操作： gen [] = [[

目前，我的代码看起来有点像这样：

gen (x:[]) = [[a] | a <- (someOp x)]
gen (x:y:[]) = [[a,b] | a <- (someOp x), b <- (someOp y)]
gen (x:y:z:[]) = [[a,b,c] | a <- (someOp x), b <- (someOp y), c <- (someOp z)]

gen（x:[]）=[[a]| a您可以递归执行此操作：


gen [] = [[]]
gen (x:xs) = [ a:g | a <- someOp x, g <- gen xs ]



gen[]=[]]

gen（x:xs）=[a:g | a对于您在此构造的函数，已经存在一个更通用的函数：。您的
gen
等效于：


gen = traverse someOp


gen=traverse someOp
您想做什么？将someOp应用于列表并将其放入第二个列表中？在函数中添加类型可能会对您有所帮助