在lua中显示表的内容
我要做的是在Lua中使用以下代码显示表的内容在lua中显示表的内容,lua,lua-table,Lua,Lua Table,我要做的是在Lua中使用以下代码显示表的内容 local people = { { name = "Fred", address = "16 Long Street", phone = "123456" }, { name = "Wilma", address = "16 Long Street", phone = "123456" }, { name = "Barney", address = "17 Long
local people = {
{
name = "Fred",
address = "16 Long Street",
phone = "123456"
},
{
name = "Wilma",
address = "16 Long Street",
phone = "123456"
},
{
name = "Barney",
address = "17 Long Street",
phone = "123457"
}
}
for k, v in pairs(people ) do
print(k, v)
end
我得到的结果是:
1 table: 0x9a2d8b0
2 table: 0x9a2d110
3 table: 0x9a2cb28
要显示嵌套表,必须使用嵌套循环 另外,用于迭代类似于数组的表,以及迭代类似于记录的表
local people = {
{
name = "Fred",
address = "16 Long Street",
phone = "123456"
},
{
name = "Wilma",
address = "16 Long Street",
phone = "123456"
},
{
name = "Barney",
address = "17 Long Street",
phone = "123457"
}
}
for index, data in ipairs(people) do
print(index)
for key, value in pairs(data) do
print('\t', key, value)
end
end
输出:
1
phone 123456
name Fred
address 16 Long Street
2
phone 123456
name Wilma
address 16 Long Street
3
phone 123457
name Barney
address 17 Long Street
这将递归地序列化一个表。此代码的变体可用于从表生成JSON
function tprint (tbl, indent)
if not indent then indent = 0 end
local toprint = string.rep(" ", indent) .. "{\r\n"
indent = indent + 2
for k, v in pairs(tbl) do
toprint = toprint .. string.rep(" ", indent)
if (type(k) == "number") then
toprint = toprint .. "[" .. k .. "] = "
elseif (type(k) == "string") then
toprint = toprint .. k .. "= "
end
if (type(v) == "number") then
toprint = toprint .. v .. ",\r\n"
elseif (type(v) == "string") then
toprint = toprint .. "\"" .. v .. "\",\r\n"
elseif (type(v) == "table") then
toprint = toprint .. tprint(v, indent + 2) .. ",\r\n"
else
toprint = toprint .. "\"" .. tostring(v) .. "\",\r\n"
end
end
toprint = toprint .. string.rep(" ", indent-2) .. "}"
return toprint
end
通过以下步骤运行表:
local people = {
{
name = "Fred",
address = "16 Long Street",
phone = "123456"
},
{
name = "Wilma",
address = "16 Long Street",
phone = "123456"
},
{
name = "Barney",
address = "17 Long Street",
phone = "123457"
}
}
print (tprint(people))
生成以下内容:
{
[1] = {
name= "Fred",
phone= "123456",
address= "16 Long Street",
},
[2] = {
name= "Wilma",
phone= "123456",
address= "16 Long Street",
},
[3] = {
name= "Barney",
phone= "123457",
address= "17 Long Street",
},
}
如果在数据记录中有静态预定义字段名,则此更简单的版本可能适用于您:
for i,t in ipairs(people) do
print('Record',i)
print('Name',t.name)
print('Address',t.address)
print('Phone',t.phone)
print()
end
我不确定你用的是什么IDE。但是,无论出于何种原因,您和任何其他发现此线程的人都在Visual Studio代码中工作,将在显示您构建的自定义表的所有关联数组值方面做得非常好 我真正喜欢的是,您不仅可以显示初始值,而且如果您决定以后更改值,您可以使用此扩展来执行此操作,并通过“调试控制台”选项卡查看您的调整
我以您的例子为例,只需在调试中输入人员,然后查看所有显示的值。解决方案1:
py.repr
$wgethttps://raw.githubusercontent.com/waketzheng/luapy/main/python.lua
py=require('python')
> tab = { 1, 2, 3 }
> py.repr(tab)
[
1,
2,
3
]
> tab = { a=1, b=2, c=3 }
> py.repr(tab)
{
"c": 3,
"a": 1,
"b": 2
}
> tab = { a='a', b='b', c='c', d='d', e='e', f='f', g='g' }
> py.repr(tab)
{
"g": "g",
"a": "a",
"b": "b",
"c": "c",
"d": "d",
...
}
> lu = require('luaunit')
> t1 = {1,2,3}
> t1['toto'] = 'titi'
> t1.f = function () end
> t1.fa = (1 == 0)
> t1.tr = (1 == 1)
> print( lu.prettystr(t1) )
{1, 2, 3, f=function: 00635d68, fa=false, toto="titi", tr=true}
解决方案2:lu.prettystr
$wgethttps://raw.githubusercontent.com/bluebird75/luaunit/main/luaunit.lua
py=require('python')
> tab = { 1, 2, 3 }
> py.repr(tab)
[
1,
2,
3
]
> tab = { a=1, b=2, c=3 }
> py.repr(tab)
{
"c": 3,
"a": 1,
"b": 2
}
> tab = { a='a', b='b', c='c', d='d', e='e', f='f', g='g' }
> py.repr(tab)
{
"g": "g",
"a": "a",
"b": "b",
"c": "c",
"d": "d",
...
}
> lu = require('luaunit')
> t1 = {1,2,3}
> t1['toto'] = 'titi'
> t1.f = function () end
> t1.fa = (1 == 0)
> t1.tr = (1 == 1)
> print( lu.prettystr(t1) )
{1, 2, 3, f=function: 00635d68, fa=false, toto="titi", tr=true}
假设您的数据结构是JSON可序列化的(如上面的示例),您可以欺骗并使用(MIT许可证)来帮助打印漂亮的对象。只要投入到您的项目中,这将起作用:
json=需要“json”
对于k,v成对(人)做
打印(k,json.encode(v))
结束
这样做的好处是,您可以选择字段显示的顺序。非常感谢。这真是太棒了helpful@Oka如何动态地判断表是类似于数组还是类似于记录?