Lua 需要名称中带有点的文件夹中的模块

我想从名称中包含点（.）的文件夹中获取文件：

如果文件夹名称中没有点，我将使用：

require(Folder.test)

---

当点存在时，我应该怎么做？

需要

使用加载程序查找文件，您可以通过将函数插入到

包中来添加自定义加载程序。加载程序

您的自定义加载程序可能如下所示：

local function load(modulename)
  local errmsg = ""
  for path in string.gmatch(package.path, "([^;]+)") do
    local filename = string.gsub(path, "%?", modulename)
    local file = io.open(filename, "rb")
    if file then
      -- Compile and return the module
      return assert(loadstring(assert(file:read("*a")), filename))
    end
    errmsg = errmsg.."\n\tno file '"..filename.."' (checked with custom loader)"
  end
  return errmsg
end

table.insert(package.loaders, 2, load) -- this will run before the standard loader, if you want it to
                                       -- run after you can call table.insert(package.loaders, load)

资源：

---

我认为您可以添加自定义加载程序/搜索程序

local function load(modulename)
  local errmsg = ""
  for path in string.gmatch(package.path, "([^;]+)") do
    local filename = string.gsub(path, "%?", modulename)
    local file = io.open(filename, "rb")
    if file then
      -- Compile and return the module
      return assert(loadstring(assert(file:read("*a")), filename))
    end
    errmsg = errmsg.."\n\tno file '"..filename.."' (checked with custom loader)"
  end
  return errmsg
end

table.insert(package.loaders, 2, load) -- this will run before the standard loader, if you want it to
                                       -- run after you can call table.insert(package.loaders, load)