lua redis.call(…)与redis中的相同调用不同
考虑代码:lua redis.call(…)与redis中的相同调用不同,lua,redis,Lua,Redis,考虑代码: redis> RPUSH test 1 (integer) 1 redis> RPUSH test 2 (integer) 2 redis> RPUSH test 19 (integer) 3 redis> RPUSH test 20 (integer) 4 redis> RPUSH test 3 (integer) 5 redis> SORT test BY nosort 1) "1" 2) "2" 3) "19" 4) "20" 5) "3"
redis> RPUSH test 1
(integer) 1
redis> RPUSH test 2
(integer) 2
redis> RPUSH test 19
(integer) 3
redis> RPUSH test 20
(integer) 4
redis> RPUSH test 3
(integer) 5
redis> SORT test BY nosort
1) "1"
2) "2"
3) "19"
4) "20"
5) "3"
redis 127.0.0.1:6379> eval "return redis.call('SORT', 'test', 'BY', 'nosort')" 0
1) "1"
2) "19"
3) "2"
4) "20"
5) "3"
redis 127.0.0.1:6379>
相同的操作,但lua返回排序顺序已损坏的列表。是虫子吗
我使用redis-2.6.0-rc7是的,它是一个bug,而且