Macos 调用TransformProcessType（）时，应用程序菜单不显示'；我没有出现

如果像这样调用TransformProcessType（）：

ProcessSerialNumber psn = { 0, kCurrentProcess }; 
(void) TransformProcessType(&psn, kProcessTransformToForegroundApplication);

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然后，除非你在应用程序中提前调用cocoa应用程序菜单（例如，在applicationWillFinishLaunching中），否则不会显示cocoa应用程序菜单。

我向苹果寻求帮助，他们帮了我很大的忙。引述：

调用TransformProcessType时菜单栏不显示的原因是，您的应用程序已经是活动应用程序（即，[[NSRunningApplication currentApplication]isActive]返回YES]），并且应用程序的菜单栏在激活应用程序时显示

这是他们的解决办法：

- (void)transformStep1 {
    for (NSRunningApplication * app in [NSRunningApplication runningApplicationsWithBundleIdentifier:@"com.apple.finder"]) {
        [app activateWithOptions:NSApplicationActivateIgnoringOtherApps];
        break;
    }
    [self performSelector:@selector(transformStep2) withObject:nil afterDelay:0.1];
}

- (void)transformStep2
{
    ProcessSerialNumber psn = { 0, kCurrentProcess }; 
    (void) TransformProcessType(&psn, kProcessTransformToForegroundApplication);

    [self performSelector:@selector(transformStep3) withObject:nil afterDelay:0.1];
}

- (void)transformStep3
{
    [[NSRunningApplication currentApplication] activateWithOptions:NSApplicationActivateIgnoringOtherApps];
}

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下面是我如何让它工作的

BOOL MakeAppForeground()
{
    BOOL bSuccess = TranformAppToState(kProcessTransformToForegroundApplication);

    if(bSuccess)
    {
         bSuccess = (SetSystemUIMode(kUIModeNormal, 0) == 0);
        [NSApp activateIgnoringOtherApps:YES];
    }

    return bSuccess;
}

BOOL MakeAppBackground()
{
    return TranformAppToState(kProcessTransformToBackgroundApplication);
}

BOOL TranformAppToState(ProcessApplicationTransformState newState)
{
    ProcessSerialNumber psn = { 0, kCurrentProcess };
    OSStatus transformStatus = TransformProcessType(&psn, newState);

    if((transformStatus != 0))
    {
        NSError *error = [NSError errorWithDomain:NSOSStatusErrorDomain code:transformStatus userInfo:nil];
        NSLog(@"TranformAppToState: Unable to transform App state. Error - %@",error);
    }

    return (transformStatus == 0);
}

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我得到了答案，但因为我的声誉太低，我只能在8小时内回答。我会尝试添加评论。我向苹果寻求帮助，他们帮了我很大的忙。Quote:>调用TransformProcessType时菜单栏不显示的原因是您的应用程序已经是活动应用程序（即，[[NSRunningApplication currentApplication]isActive]返回YES]），并且应用程序的菜单栏在激活应用程序时显示这是他们的解决方法：-（void）transformStep1{for（NSRunningApplication*app在[NSRunningApplication runningApplicationsWithBundleIdentifier:@“com.apple.finder”]{[app activatedethodoptions:nsapplicationactivatedignoringotherapps]；break；}[selector:@selector（transformStep2）with object:nil afterDelay:0.1]；}-（void）transformStep2{ProcessSerialNumber psn={0，kCurrentProcess}；（void）TransformProcessType（&psn，kProcessTransformToForegroundApplication）；[self-performSelector:@selector（transformStep3）with Object:nil afterDelay:0.1]；}-（void）transformStep3{[[nsrunning Application currentApplication]ActivateWithoOptions:NSApplicationActivateIgnoringOtherApps]；}我使用了@“com.apple.dock”。这似乎比激活Finder使其跳转到前台要好。