GNU Makefile替换引用问题：使用%2次

我试图使用GNUMake的替换引用，但我需要在替换中引用%两次。而且它没有按照我预期的方式工作。这是我的Makefile：

foo := io protocol util
bar := $(foo:%=../Lib%/obj/lib%.a)

default: ; @echo bar = $(bar)

我想以以下方式结束：

../Libio/obj/lib%.a ../Libprotocol/obj/lib%.a ../Libutil/obj/lib%.a```

I've read the GNU Make reference manual, and I don't see any mention or examples of using % twice in one statement. I don't even know if it is possible.

Any help would be greatly appreciated.

bar=../Libio/obj/Libio.a../Libprotocol/obj/Libprotocol.a../Libutil/obj/Libutil.a

但这就是我的结局：

../Libio/obj/lib%.a ../Libprotocol/obj/lib%.a ../Libutil/obj/lib%.a```

I've read the GNU Make reference manual, and I don't see any mention or examples of using % twice in one statement. I don't even know if it is possible.

Any help would be greatly appreciated.

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正如您通过阅读手册所发现的，不可能使用该模式两次。只有第一个字符被扩展：其余的被简单地认为是文字字符

您可以改用

foreach

功能：

bar := $(foreach F,$(foo),../Lib$F/obj/lib$F.a)

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完美的非常感谢。