Makefile CMake忽略传递给';目标链接库';
我有一组自定义库,我正在尝试使用我编写的CMake文件构建它们。当前目录结构如下所示:Makefile CMake忽略传递给';目标链接库';,makefile,cmake,linker,linker-errors,Makefile,Cmake,Linker,Linker Errors,我有一组自定义库,我正在尝试使用我编写的CMake文件构建它们。当前目录结构如下所示: ├── lib ├── src │ ├── ac_d │ ├── at_d │ ├── bp_d │ ├── fm_d │ ├── hm_d │ ├── pi_d │ ├── pv_d │ ├── ra_d │ └── rc_d └── test 我的目标是让编译器在链接/src目录中的可执行文件时使用/lib目录中构建的.so文件。我尝试了以下方法,但没有效果: 在顶级
├── lib
├── src
│ ├── ac_d
│ ├── at_d
│ ├── bp_d
│ ├── fm_d
│ ├── hm_d
│ ├── pi_d
│ ├── pv_d
│ ├── ra_d
│ └── rc_d
└── test
我的目标是让编译器在链接/src
目录中的可执行文件时使用/lib
目录中构建的.so文件。我尝试了以下方法,但没有效果:
在顶级CMakeLists.txt中:
/* minimum version, project name etc */
set(CMAKE_PREFIX_PATH ${CMAKE_PREFIX_PATH} ${CMAKE_CURRENT_SOURCE_DIR}/lib)
set(CMAKE_LIBRARY_PATH ${CMAKE_LIBRARY_PATH} ${CMAKE_CURRENT_SOURCE_DIR}/lib)
/* other stuff */
set(CDH_LIB_NAMES comm daemon debug tty sock)
set(CDH_LIB_INCLUDES
${CMAKE_CURRENT_SOURCE_DIR}/lib/global.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libcomm.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libdaemon.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libdebug.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libtty.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libsock.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/uthash.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/utlist.h)
add_subdirectory(lib) # make sure we build .so first
include_directories(lib) # then use this as an include directory
link_directories(${CMAKE_CURRENT_SOURCE_DIR}/lib) # and a link directory
find_library(CDH_LIBS
NAMES tty comm sock debug daemon
PATHS "${CMAKE_CURRENT_SOURCE_DIR}/lib"
) # Not sure if this does anything
add_subdirectory(src) # Now build the src binaries
set(ACD_BIN ACdtest)
set(ACD_SRC
${CMAKE_CURRENT_SOURCE_DIR}/ACd.c
${CMAKE_CURRENT_SOURCE_DIR}/ACd.h
${CDH_LIB_INCLUDES})
add_executable(${ACD_BIN} ${ACD_SRC})
target_link_libraries(${ACD_BIN} ${CDH_LIB_NAMES})
我还听说您可以使用target\u link\u libraries()
,因此我在所有`src/*/CMakeLists.txt中添加了类似的行:
/* minimum version, project name etc */
set(CMAKE_PREFIX_PATH ${CMAKE_PREFIX_PATH} ${CMAKE_CURRENT_SOURCE_DIR}/lib)
set(CMAKE_LIBRARY_PATH ${CMAKE_LIBRARY_PATH} ${CMAKE_CURRENT_SOURCE_DIR}/lib)
/* other stuff */
set(CDH_LIB_NAMES comm daemon debug tty sock)
set(CDH_LIB_INCLUDES
${CMAKE_CURRENT_SOURCE_DIR}/lib/global.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libcomm.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libdaemon.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libdebug.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libtty.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/libsock.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/uthash.h
${CMAKE_CURRENT_SOURCE_DIR}/lib/utlist.h)
add_subdirectory(lib) # make sure we build .so first
include_directories(lib) # then use this as an include directory
link_directories(${CMAKE_CURRENT_SOURCE_DIR}/lib) # and a link directory
find_library(CDH_LIBS
NAMES tty comm sock debug daemon
PATHS "${CMAKE_CURRENT_SOURCE_DIR}/lib"
) # Not sure if this does anything
add_subdirectory(src) # Now build the src binaries
set(ACD_BIN ACdtest)
set(ACD_SRC
${CMAKE_CURRENT_SOURCE_DIR}/ACd.c
${CMAKE_CURRENT_SOURCE_DIR}/ACd.h
${CDH_LIB_INCLUDES})
add_executable(${ACD_BIN} ${ACD_SRC})
target_link_libraries(${ACD_BIN} ${CDH_LIB_NAMES})
由于某种原因,我仍然得到未定义的引用。因此,我尝试用make VERBOSE=1 pi-d
编译一个这样的二进制文件,并得到以下输出(为了简洁起见,仅相关行):
看起来它只得到了
libcomm
,libdaemon
和libsock
,忽略了libdebug
和libtty
。为什么会这样?我可以更改什么?debug
是命令的关键字
与该关键字后面的库的链接仅针对“Debug”配置执行,这可能不是您的情况。
Debug
是命令的关键字
该关键字后面的库链接仅针对“Debug”配置执行,这可能不是您的情况。我通过简单地将目标重命名为
Debug_lib
解决了这个问题
add_library(debug_lib SHARED ${DEBUG_LIB_SRC})
这导致生成的库被称为
libdebug\u lib.so
,但这对我来说没什么问题。我只需将目标重命名为debug\u lib
,就解决了这个问题
add_library(debug_lib SHARED ${DEBUG_LIB_SRC})
这导致生成的库被称为
libdebug\u lib.so
,但这对我来说没关系。我正在尝试实现您在这里给出的答案:并遇到了“找不到-ldebug\u lib”的问题,我正在尝试实现你在这里给出的答案:并遇到了“找不到-ldebug_lib”的问题,这似乎是在翻译中丢失了一些东西。