Mongodb 如何减去时间序列元素以获得与之前日期的差异?
我正在尝试在Mongo Atlas中构建仪表板图表。 表格应在x轴上显示日期,在y轴上显示id。 这些值应为与之前日期的计数差 我收集了一些数据点,例如:Mongodb 如何减去时间序列元素以获得与之前日期的差异?,mongodb,mongodb-query,mongodb-atlas,Mongodb,Mongodb Query,Mongodb Atlas,我正在尝试在Mongo Atlas中构建仪表板图表。 表格应在x轴上显示日期,在y轴上显示id。 这些值应为与之前日期的计数差 我收集了一些数据点,例如: _id: "someName" timestamp: 2019-09-05T06:24:24.689+00:00 count: 50 _id: "someName" timestamp: 2019-09-04T06:24:24.689+00:00 count: 40 ... 目标是获得计数与之前数据点的差值。同名的有相同名字的 _id:
_id: "someName"
timestamp: 2019-09-05T06:24:24.689+00:00
count: 50
_id: "someName"
timestamp: 2019-09-04T06:24:24.689+00:00
count: 40
...
目标是获得计数与之前数据点的差值。同名的有相同名字的
_id: "someName"
timestamp: 2019-09-05T06:24:24.689+00:00
count: 50
difference: 10
_id: "someName"
timestamp: 2019-09-04T06:24:24.689+00:00
count: 40
difference: 17
...
这样我就可以制作一个表格,列出不同之处
到目前为止,我创建了一个聚合管道
[
{$sort: {
"timestamp": -1
}},
{$group: {
_id: "$_id",
count: {
$push: { count: "$count", timestamp: "$timestamp" }
}
}},
{$project: {
_id: "$_id",
count: "$count",
countBefore: { $slice: [ "$count", 1, { $size: "$count" } ] }
}}
]
我希望减去count和countBefore,这样我就得到了一个数据点和差值的数组
所以我试着用:
{$project: {
countDifference: {
$map: {
input: "$countBefore",
as: "before",
in: {
$subtract: ["$$before.count", "$count.count"]
/*"$count.count" seems to be the problem, since an integer works*/
}
}
}
}
}
Mongo Atlas仅显示“发生未知错误”
我很乐意得到一些建议:)以下查询可以为我们提供预期的输出:
db.collection.aggregate([
{
$sort:{
"timestamp":1
}
},
{
$group:{
"_id":"$id",
"counts":{
$push:"$count"
}
}
},
{
$project:{
"differences":{
$reduce:{
"input":"$counts",
"initialValue":{
"values":[],
"lastValue":0
},
"in":{
"values":{
$concatArrays:[
"$$value.values",
[
{
$subtract:["$$this","$$value.lastValue"]
}
]
]
},
"lastValue":"$$this"
}
}
}
}
},
{
$project:{
"_id":0,
"id":"$_id",
"plots":"$differences.values"
}
}
]).pretty()
数据集:
{
"_id" : ObjectId("5d724550ef5e6630fde5b71e"),
"id" : "someName",
"timestamp" : "2019-09-05T06:24:24.689+00:00",
"count" : 50
}
{
"_id" : ObjectId("5d724550ef5e6630fde5b71f"),
"id" : "someName",
"timestamp" : "2019-09-04T06:24:24.689+00:00",
"count" : 40
}
{
"_id" : ObjectId("5d724796ef5e6630fde5b720"),
"id" : "someName",
"timestamp" : "2019-09-06T06:24:24.689+00:00",
"count" : 61
}
{
"_id" : ObjectId("5d724796ef5e6630fde5b721"),
"id" : "someName",
"timestamp" : "2019-09-07T06:24:24.689+00:00",
"count" : 72
}
{
"_id" : ObjectId("5d724796ef5e6630fde5b722"),
"id" : "someName",
"timestamp" : "2019-09-08T06:24:24.689+00:00",
"count" : 93
}
{
"_id" : ObjectId("5d724796ef5e6630fde5b723"),
"id" : "someName",
"timestamp" : "2019-09-09T06:24:24.689+00:00",
"count" : 100
}
{ "id" : "someName", "plots" : [ 40, 10, 11, 11, 21, 7 ] }
输出:
{
"_id" : ObjectId("5d724550ef5e6630fde5b71e"),
"id" : "someName",
"timestamp" : "2019-09-05T06:24:24.689+00:00",
"count" : 50
}
{
"_id" : ObjectId("5d724550ef5e6630fde5b71f"),
"id" : "someName",
"timestamp" : "2019-09-04T06:24:24.689+00:00",
"count" : 40
}
{
"_id" : ObjectId("5d724796ef5e6630fde5b720"),
"id" : "someName",
"timestamp" : "2019-09-06T06:24:24.689+00:00",
"count" : 61
}
{
"_id" : ObjectId("5d724796ef5e6630fde5b721"),
"id" : "someName",
"timestamp" : "2019-09-07T06:24:24.689+00:00",
"count" : 72
}
{
"_id" : ObjectId("5d724796ef5e6630fde5b722"),
"id" : "someName",
"timestamp" : "2019-09-08T06:24:24.689+00:00",
"count" : 93
}
{
"_id" : ObjectId("5d724796ef5e6630fde5b723"),
"id" : "someName",
"timestamp" : "2019-09-09T06:24:24.689+00:00",
"count" : 100
}
{ "id" : "someName", "plots" : [ 40, 10, 11, 11, 21, 7 ] }
解释:我们将同一
id
的count
推送到counts
数组中,然后对其应用操作以准备一组新值,其中当前值将保留counts
数组的当前值和以前值之间的差异。对于第一个值,前一个值被视为零。非常感谢。这似乎起到了作用,解释对我的进一步应用有很大帮助。