更新MongoDB中的嵌套数组文档
所以我有一个像这样的mongo文档,我需要根据val更新数组更新MongoDB中的嵌套数组文档,mongodb,mongo-java-driver,Mongodb,Mongo Java Driver,所以我有一个像这样的mongo文档,我需要根据val更新数组 { "_id" : NumberLong(222), "pattern":"grain" "BASIC" : { "frame":"clear" "tin" : [ { "val" : "abc", "unit" : NumberLong(2311) }, { "val" : "def",
{
"_id" : NumberLong(222),
"pattern":"grain"
"BASIC" : {
"frame":"clear"
"tin" : [
{
"val" : "abc",
"unit" : NumberLong(2311)
},
{
"val" : "def",
"unit" : NumberLong(2311)
},
]
}
}
这是我试过的代码
collection = db.getCollection("test");
Bson where = new Document().append("_id", 222).append("BASIC.tin.val","abc");
Bson update = new Document()
.append("BASIC.tin.$.val", "xyz");
Bson set = new Document().append("$set", update);
try {
UpdateResult result = collection.updateOne(where , set, new UpdateOptions().upsert(true));
if(result.getMatchedCount()>0){
System.out.println("updated");
System.out.println(result.getModifiedCount());
}else{
System.out.println("failed");
}
} catch (MongoWriteException e) {
e.printStackTrace();
}
更新工作正常,但如果查找失败,则不会取消插入
这是我得到的错误:
com.mongodb.MongoWriteException:位置运算符未从查询中找到所需的匹配项。未扩展的更新:BASIC.tin.$.val
位于com.mongodb.MongoCollectionImpl.executeSingleWriteRequest(MongoCollectionImpl.java:558)
在com.mongodb.MongoCollectionImpl.update(MongoCollectionImpl.java:542)中,无法向嵌入文档中插入,因此会出现错误。因此,为了模拟嵌入式文档的upsert,您需要像下面这样更新代码。这将检查修改的计数,如果它为0,则意味着我们需要在嵌入的文档中插入一个新文档,该文档利用push进行此操作。这将对您拥有的示例文档执行一个upsert,其中“pqr”为val,“unit”为400
Bson where = new Document().append("_id", 222).append("BASIC.tin.val","pqr");
Bson update = new Document()
.append("BASIC.tin.$.val", "xyz");
Bson set = new Document().append("$set", update);
try {
UpdateResult result = collection.updateOne(where , set, new UpdateOptions());
if(result.getModifiedCount() > 0){
System.out.println("updated");
} else if(result.getModifiedCount()==0){
System.out.println("upserting");
Bson where1 = new Document().append("_id", 222);
Bson upsert = new Document().append("BASIC.tin", new Document().append("val", "pqr").append("unit", 400));;
Bson push = new Document().append("$push", upsert);
UpdateResult result1 = collection.updateOne(where1 , push, new UpdateOptions());
if(result1.getModifiedCount() == 1)
System.out.println("upserted");
}else {
System.out.println("failed");
}
} catch (MongoWriteException e) {
e.printStackTrace();
}
upsert后的样本响应
{
"_id": NumberLong(222),
"pattern": "grain",
"BASIC": {
"frame": "clear",
"tin": [{
"val": "xyz",
"unit": NumberLong(2311)
}, {
"val": "def",
"unit": NumberLong(2311)
}, {
"val": "pqr",
"unit": 400
}]
}
}
您是否正在尝试插入嵌入的文档“tin”?