Ms access 执行不包含指定聚合函数错误消息的查询

我有以下查询返回错误消息

“您试图执行不包含指定表达式的查询”

现在，如果我在

GROUPBY

子句中包含o.ea\u guid和o.object\u类型，则不会返回任何结果

我做错了什么？

计数（o.name）是一个集合；其他属性则不是。如果要显示非聚合，必须将其放入GROUPBY子句中。这将为CLASSGUID、CLASSTYPE和NAME三个字段的每个唯一组合提供行数

SELECT 
    o.ea_guid as CLASSGUID, 
    o.object_type as CLASSTYPE,
    o.name as NAME, 
    COUNT(*) as NameCount
FROM 
    t_object as o
GROUP BY 
    o.ea_guid, 
    o.object_type,
    o.name

HAVING 
    (COUNT(*)>1)

---

这可能不是你想要的

查询有两个错误：

o.ea_guid as CLASSGUID, o.object_type as CLASSTYPE 

这意味着结果将被引用到企业架构师模型中的特定工件，因此您不能在企业架构师的拒绝查询中使用它。使用：

SELECT o.name, COUNT(o.name) as NameCount
FROM t_object as o
GROUP BY o.name
HAVING (COUNT(o.name)>1)

或所有选定的房型都应分组：

SELECT o.ea_guid as CLASSGUID, o.object_type as CLASSTYPE, o.name, COUNT(o.name) as NameCount
FROM t_object as o
GROUP BY o.ea_guid , o.object_type , o.name
HAVING (COUNT(o.name)>1)

---

在这种情况下，这似乎很愚蠢，但也不起作用。我收到消息

“您试图执行的查询未将指定的表达式“Name”作为聚合函数的一部分”

。如果我将其包含在

GROUP BY

子句中，则不会返回任何结果。很抱歉，有一个输入错误-我做了一个快速更改，但忘记将

o.name

添加到GROUP BY子句中。我现在已经在上面添加了它。你知道为什么会出现这种错误吗？

SELECT o.ea_guid as CLASSGUID, o.object_type as CLASSTYPE, o.name, COUNT(o.name) as NameCount
FROM t_object as o
GROUP BY o.ea_guid , o.object_type , o.name
HAVING (COUNT(o.name)>1)