Ms access 按名称获取文本框-访问
我正面临以下pbm 问题:Ms access 按名称获取文本框-访问,ms-access,vba,Ms Access,Vba,我正面临以下pbm 问题: If InputLibelle.Value <> Me!SubStockEdit!DSLibelle.Value Then Dim TableColumnNames() As String TableColumnNames = Split("Poids, Dimension1, Dimension2, Dimension3, Description, Price", ",
If InputLibelle.Value <> Me!SubStockEdit!DSLibelle.Value Then
Dim TableColumnNames() As String
TableColumnNames = Split("Poids, Dimension1, Dimension2,
Dimension3, Description, Price", ",")
For Each ColumnName In TableColumnNames
If Me.Name("Input" & ColumnName).Value <> ???
Next
我想知道通过字符串调用TextBox/ComboBox的.value的方法
示例:
If InputLibelle.Value <> Me!SubStockEdit!DSLibelle.Value Then
Dim TableColumnNames() As String
TableColumnNames = Split("Poids, Dimension1, Dimension2,
Dimension3, Description, Price", ",")
For Each ColumnName In TableColumnNames
If Me.Name("Input" & ColumnName).Value <> ???
Next
如果输入libelle.Value Me!子剪辑!DSLibelle.Value然后
我想多次比较子窗体数据表(SubStockEdit!DS+ItemName)中的ItemName文本框的值(输入+ItemName)和另一个文本框的值
代码尝试:
If InputLibelle.Value <> Me!SubStockEdit!DSLibelle.Value Then
Dim TableColumnNames() As String
TableColumnNames = Split("Poids, Dimension1, Dimension2,
Dimension3, Description, Price", ",")
For Each ColumnName In TableColumnNames
If Me.Name("Input" & ColumnName).Value <> ???
Next
Dim TableColumnNames()作为字符串
TableColumnNames=拆分(“POID,维度1,维度2,
尺寸3,说明,价格“,”,”)
对于TableColumnNames中的每个ColumnName
如果Me.Name(“输入”&ColumnName).Value???
下一个
有人知道如何调用这些对象吗?那就是:
Dim TableColumnNames() As String
TableColumnNames = Split("Poids, Dimension1, Dimension2, Dimension3, Description, Price", ",")
For Each ColumnName In TableColumnNames
If Me("Input" & ColumnName).Value <> Me!SubStockEdit("DS" & ColumnName).Value Then
' Do stuff.
End If
Next
Dim TableColumnNames()作为字符串
TableColumnNames=拆分(“POID,维度1,维度2,维度3,描述,价格“,”,”)
对于TableColumnNames中的每个ColumnName
如果我(“输入”&列名)。请为我估价!SubStockEdit(“DS”和ColumnName)。然后
“做点什么。
如果结束
下一个
或者这种扩展语法:
If Me("Input" & ColumnName).Value <> Me!SubStockEdit.Form("DS" & ColumnName).Value Then
If-Me(“输入”&ColumnName)。给我赋值!SubStockEdit.Form(“DS”&ColumnName).Value然后
试试这个
Controls("Input" & ColumnName).Name
Controls("Input" & ColumnName).Value
Me!SubStockEdit!Form.Controls("Input" & ColumnName).Value
eval("Input" & ColumnName)
eval("Me!SubStockEdit!DSLibelle")
谢谢你的回答。