Mysql 将两个查询放入同一个表（按日期分组）

我正在用MySQL数据库尝试我的第一个select语句，当你不知道用谷歌搜索什么的时候，这非常困难

这就是我要做的，我有两个问题：

select date(server_time) as d, count(*) as x
from table_A, table_B 
where date(server_time) >= '2015-07-17'  
and table_A.id = table_B.id    
and idname is not null
and idurl is not null        
group by date(server_time)

及

我试图实现的是将两个计数列与日期结合在一起：

d               x     y
-------------|-----|-------
2015-07-17   |  3  |  20
2015-07-18   |  2  |  50
2015-07-19   |  7  |  10
-------------|-----|-------

---

我一直在玩弄UNION、SELECT count等，但运气不好。

请定义x和y，并发布相关的表结构创建表代码。如果输出两个查询的实际结果，则更容易获得有用的答案。也考虑使用。顺便说一句，我打赌UNION ALL=d第一个查询得到一个包含d列和x列的表，第二个包含d列和y列。。我只想把它们合并在一起。@Kathi typo，现在试试谢谢，你忘了在内部选择中也包括id，那么它就像一个符咒！

SELECT date(server_time) AS d, 
       count(*) AS x,
       (SELECT y 
        FROM (SELECT date(server_time) AS d, 
                     id,
                     count(*) AS y
              FROM table_A 
              WHERE date(sever_time) >= '2015-07-17'
              GROUP BY date(server_time)) sub
        WHERE SUB.id = a.id) AS y
FROM table_A a
INNER JOIN table_B b ON a.id = b.id
WHERE date(server_time) >= '2015-07-17'
AND idname IS NOT NULL
AND idurl IS NOT NULL      
GROUP BY date(server_time)

SELECT date(server_time) AS d, 
       count(*) AS x,
       (SELECT y 
        FROM (SELECT date(server_time) AS d, 
                     id,
                     count(*) AS y
              FROM table_A 
              WHERE date(sever_time) >= '2015-07-17'
              GROUP BY date(server_time)) sub
        WHERE SUB.id = a.id) AS y
FROM table_A a
INNER JOIN table_B b ON a.id = b.id
WHERE date(server_time) >= '2015-07-17'
AND idname IS NOT NULL
AND idurl IS NOT NULL      
GROUP BY date(server_time)