Sql 按用户选择每列的最后一个值,这是最简单的方法
这是a的扩展版本。我已经发布了一个新的问题,建议我这样做。(在人们回答了我的第一个问题后,我意识到我其实想要这个) 具有以下数据(空白表示为空): 如何以最简单的方式为所有用户获取每列的最后一个非空值?因此,给定数据的结果为:Sql 按用户选择每列的最后一个值,这是最简单的方法,sql,null,Sql,Null,这是a的扩展版本。我已经发布了一个新的问题,建议我这样做。(在人们回答了我的第一个问题后,我意识到我其实想要这个) 具有以下数据(空白表示为空): 如何以最简单的方式为所有用户获取每列的最后一个非空值?因此,给定数据的结果为: User ColA ColB ColC 1 11 1 20 2 6 8 10 我没有发现太多类似于我描述的功能是COALESCE,但在我的例子中它并没有像预期的那样工作 注意:如果可能,标准SQ
User ColA ColB ColC
1 11 1 20
2 6 8 10
我没有发现太多类似于我描述的功能是COALESCE
,但在我的例子中它并没有像预期的那样工作
注意:如果可能,标准SQL,否则为PostgreSQL。相关列的计数可能会发生变化,因此最好采用不与这三个特定列绑定的解决方案。“标准”SQL
与我在上一个问题上发布的内容类似,在标准SQL中,a是一种优雅且可能是最快的方法,尤其是对于每个用户的多行
WITH RECURSIVE t AS (
SELECT row_number() OVER (PARTITION BY usr ORDER BY id DESC) AS rn
,usr, cola, colb, colc
FROM tbl
)
, x AS (
SELECT rn, usr, cola, colb, colc
FROM t
WHERE rn = 1
UNION ALL
SELECT t.rn, t.usr
, COALESCE(x.cola, t.cola)
, COALESCE(x.colb, t.colb)
, COALESCE(x.colc, t.colc)
FROM x
JOIN t USING (usr)
WHERE t.rn = x.rn + 1
AND (x.cola IS NULL OR x.colb IS NULL OR x.colc IS NULL)
)
SELECT DISTINCT ON (usr)
usr, cola, colb, colc
FROM x
ORDER BY usr, rn DESC;
唯一的非标准元素是上的DISTINCT,它是标准中DISTINCT
的扩展。对于标准SQL,将最后的SELECT
替换为以下内容:
SELECT usr
,max(cola) As cola
,max(colb) As colb
,max(colc) As colc
FROM x
GROUP BY usr
ORDER BY usr;
“标准SQL”的请求用途有限。该标准仅存在于纸面上。没有一个RDBMS实现100%的标准SQL——这也将是毫无意义的,因为该标准在这里和那里包含了无意义的部分。可以说,PostgreSQL的实现是最接近标准的实现之一
PL/pgSQL函数
此解决方案是特定于PostgreSQL的,但性能应该很好
我在上面小提琴所示的同一张桌子上构建
CREATE OR REPLACE FUNCTION f_last_nonull_per_user()
RETURNS SETOF tbl AS
$func$
DECLARE
_row tbl; -- table name can be used as row type
_new tbl;
BEGIN
FOR _new IN
SELECT * FROM tbl ORDER BY usr, id DESC
LOOP
IF _new.usr = _row.usr THEN
_row.id := _new.id; -- copy only id
IF _row.cola IS NULL AND _new.cola IS NOT NULL THEN
_row.cola := _new.cola; END IF; -- only if no value found yet
IF _row.colb IS NULL AND _new.colb IS NOT NULL THEN
_row.colb := _new.colb; END IF;
IF _row.colc IS NULL AND _new.colc IS NOT NULL THEN
_row.colc := _new.colc; END IF;
ELSE
IF _new.usr <> _row.usr THEN -- doesn't fire on first row
RETURN NEXT _row;
END IF;
_row := _new; -- remember row for next iteration
END IF;
END LOOP;
RETURN NEXT _row; -- return row for last usr
END
$func$ LANGUAGE plpgsql;
返回整行-包括我们需要填充所有列的minid
。此查询很容易转换为MS SQL。如果您需要更具体的内容,请添加评论。Mysql查询:
SELECT
t1.User,
(SELECT ColA
FROM Table1
WHERE ColA is not null
AND Table1.User = t1.User
ORDER BY ID DESC
LIMIT 1 ) as ColA,
(SELECT ColB
FROM Table1
WHERE ColB is not null
AND Table1.User = t1.User
ORDER BY ID DESC
LIMIT 1 ) as ColB,
(SELECT ColC
FROM Table1
WHERE ColC is not null
AND Table1.User = t1.User
ORDER BY ID DESC
LIMIT 1 ) as ColC
FROM Table1 t1
GROUP BY t1.User
结果:
| USER | COLA | COLB | COLC |
-----------------------------
| 1 | 11 | 1 | 20 |
| 2 | 6 | 8 | 10 |
哪种关系数据库管理系统?SQL Server、Oracle等?任何,我更喜欢标准SQL,或者PostgreSQL。你说的“标准SQL”是指MS SQL Server吗?哪个版本?您能提供创建表和插入的脚本吗?可以用于测试。@JeradRose-标准SQL表示符合的SQL。
SELECT
t1.User,
(SELECT ColA
FROM Table1
WHERE ColA is not null
AND Table1.User = t1.User
ORDER BY ID DESC
LIMIT 1 ) as ColA,
(SELECT ColB
FROM Table1
WHERE ColB is not null
AND Table1.User = t1.User
ORDER BY ID DESC
LIMIT 1 ) as ColB,
(SELECT ColC
FROM Table1
WHERE ColC is not null
AND Table1.User = t1.User
ORDER BY ID DESC
LIMIT 1 ) as ColC
FROM Table1 t1
GROUP BY t1.User
| USER | COLA | COLB | COLC |
-----------------------------
| 1 | 11 | 1 | 20 |
| 2 | 6 | 8 | 10 |