在mysql中使用GROUPBY时如何获取条件计数？

我是新手

我有一个表名：'audit\u webservice\u aua'如下：

+---------+------------------------------------+-------------------+------------------------+ | auditId | device_code | response_status | request_date +---------+------------------------------------+-------------------+------------------------+ | 10001 | 0007756-gyy66-4c6e-a59d-xxxccyyyt1 | P | 2020-03-02 00:00:08.785 | 10002 | 0007756-gyy66-4c6e-a59d-xxxccyyyt2 | F | 2020-04-06 00:00:08.785 | 10003 | 0007756-gyy66-4c6e-a59d-xxxccyyyt3 | F | 2020-04-01 00:01:08.785 | 10004 | 0007756-gyy66-4c6e-a59d-xxxccyyyt1 | P | 2020-05-02 00:02:08.785 | 10005 | 0007756-gyy66-4c6e-a59d-xxxccyyyt1 | P | 2020-05-09 00:03:08.785 | 10006 | 0007756-gyy66-4c6e-a59d-xxxccyyyt2 | P | 2020-05-09 01:00:08.785 | 10007 | 0007756-gyy66-4c6e-a59d-xxxccyyyt7 | F | 2020-06-06 02:00:08.785 +---------+------------------------------------+-------------------+------------------------+ 每次发出新请求时，上表存储请求设备代码、响应状态和请求时间

我需要获得结果集，其中包含两个给定日期之间每天的每个设备代码、总传输、总成功、总失败和日期

我写的问题如下：

SELECT DATE_FORMAT(aua.request_date,'%b') as month , YEAR(aua.request_date) as year, DATE_FORMAT(aua.request_date,'%Y-%m-%d') as date, (select count(aua.audit_id) )as total_trans , (select count(aua.audit_id) where aua.response_status 'P') as total_failure , (select count(aua.audit_id) where aua.response_status = 'P') as total_successful , aua.device_code as deviceCode FROM audit_webservice_aua aua where DATE_FORMAT(aua.request_date,'%Y-%m-%d') between '2020-04-16' and '2020-07-17' group by dates,deviceCode ; 在上述代码中，我尝试获取介于“2020-03-02”和“2020-06-06”之间的结果，但我获取的计数不正确。 任何帮助都将不胜感激。

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提前谢谢。

我想您只需要条件聚合：

SELECT DATE_FORMAT(aua.request_date,'%b') as month , 
       YEAR(aua.request_date) as year,
       DATE_FORMAT(aua.request_date, '%Y-%m-%d') as date,
       COUNT(aua.audit_id) as total_trans ,
       SUM(aua.response_status <> 'P') as total_failure,
       SUM(aua.response_status = 'P') as total_successful,
       aua.device_code as deviceCode
FROM audit_webservice_aua aua 
WHERE DATE_FORMAT(aua.request_date, '%Y-%m-%d') between '2020-04-16' and '2020-07-17' 
GROUP BY month, year, date, deviceCode ;

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我认为您只需要条件聚合：

SELECT DATE_FORMAT(aua.request_date,'%b') as month , 
       YEAR(aua.request_date) as year,
       DATE_FORMAT(aua.request_date, '%Y-%m-%d') as date,
       COUNT(aua.audit_id) as total_trans ,
       SUM(aua.response_status <> 'P') as total_failure,
       SUM(aua.response_status = 'P') as total_successful,
       aua.device_code as deviceCode
FROM audit_webservice_aua aua 
WHERE DATE_FORMAT(aua.request_date, '%Y-%m-%d') between '2020-04-16' and '2020-07-17' 
GROUP BY month, year, date, deviceCode ;