Mysql 从联接中选择时出错

有人知道我为什么从这个查询中得到错误吗：

SELECT COUNT(*) 
FROM individual AS i LEFT JOIN establishment AS e USING establishment_id
WHERE i.bla = e.bla;

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mysql workbench在第1行的设置id下给了我一条曲线，并报告了一个语法错误，但我不确定为什么会出现这个错误。

我想您需要括号：

SELECT COUNT(*) 
FROM individual AS i LEFT JOIN establishment AS e USING (establishment_id)
WHERE i.bla = e.bla;

试试这个

SELECT COUNT(*) 
FROM individual AS i LEFT JOIN establishment AS e USING establishment_id
on i.bla = e.bla;

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两个表中是否有同名的

机构id

？

使用（机构id）