Mysql HAVING子句中的多重聚合函数

由于我查询的性质，我有计数为3的记录，这也符合计数为2的条件，依此类推。我想知道是否可以查询“计数大于x且小于7”？我怎么能写这个。这是我目前的代码

GROUP BY meetingID
HAVING COUNT( caseID )<4

按会议ID分组
按会议ID分组计数（案例ID）

计数（caseID）<4且计数（caseID）>2
对于您的示例查询，唯一可能大于2小于4的值是3，因此我们简化了：

GROUP BY meetingID
HAVING COUNT(caseID) = 3


在一般情况下：

GROUP BY meetingID
HAVING COUNT(caseID) > x AND COUNT(caseID) < 7

不需要进行两次检查，为什么不只检查计数=3：

GROUP BY meetingID
HAVING COUNT(caseID) = 3

如果要使用多个检查，则可以使用：

GROUP BY meetingID
HAVING COUNT(caseID) > 2
 AND COUNT(caseID) < 4

按会议ID分组
计数（案例ID）>2
和计数（caseID）<4
像这样的东西

HAVING COUNT(caseID) > 2
AND COUNT(caseID) < 4

计数（caseID）>2
和计数（caseID）<4
我在这里写下完整的查询，这将消除您所有的疑问

SELECT BillingDate,
       COUNT(*) AS BillingQty,
       SUM(BillingTotal) AS BillingSum
FROM Billings
WHERE BillingDate BETWEEN '2002-05-01' AND '2002-05-31'
GROUP BY BillingDate
HAVING COUNT(*) > 1
AND SUM(BillingTotal) > 100
ORDER BY BillingDate DESC

欢迎光临！你最好解释一下你做了什么。你能在回答中包括这一点吗？谢谢
GROUP BY meetingID
HAVING COUNT(caseID) > 2
 AND COUNT(caseID) < 4

HAVING COUNT(caseID) > 2
AND COUNT(caseID) < 4

select CUSTOMER_CODE,nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) DEBIT,nvl(sum(DECODE(TRANSACTION_TYPE,'C',AMOUNT)),0)) CREDIT,
nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) - nvl(sum(DECODE(TRANSACTION_TYPE,'C',AMOUNT)),0)) BALANCE from TRANSACTION   
GROUP BY CUSTOMER_CODE
having nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) > 0
AND (nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) - nvl(sum(DECODE(TRANSACTION_TYPE,'C',AMOUNT)),0))) > 0

SELECT BillingDate,
       COUNT(*) AS BillingQty,
       SUM(BillingTotal) AS BillingSum
FROM Billings
WHERE BillingDate BETWEEN '2002-05-01' AND '2002-05-31'
GROUP BY BillingDate
HAVING COUNT(*) > 1
AND SUM(BillingTotal) > 100
ORDER BY BillingDate DESC