Mysql在multiselect中求和

我要总价（含税）和已付的总价。如果使用第一个查询，则从所有选定列中获取行。这个很好用。但我只想要总数，所以我更改了查询

SELECT 
total_price_incl_tax,
(SELECT SUM(amount) AS total FROM `invoice_payments` WHERE `invoice_id` = s.id AND invoice_type = 'sales') as paid
FROM sales_invoices AS s 
WHERE s.administration_id = 10605 
AND `s`.`delete` = '0' 
AND `s`.`concept` = '0' 
AND `s`.`subscription` = '0' 
AND (`total_price_incl_tax` <> (SELECT SUM(`amount`) AS sum FROM `invoice_payments` WHERE `invoice_id` = s.id AND invoice_type = 'sales') OR (SELECT SUM(amount) AS sum FROM `invoice_payments` WHERE `invoice_id` = s.id AND invoice_type = 'sales') IS NULL)

第二个查询的问题是子查询的支付金额不正确。它包含最后一行的值，而不是总数

SELECT 
COUNT(*),
SUM(total_price_incl_tax) AS total,
(SELECT SUM(amount) AS total FROM `invoice_payments` WHERE `invoice_id` = s.id AND invoice_type = 'sales') as paid
FROM sales_invoices AS s 
WHERE s.administration_id = 10605 
AND `s`.`delete` = '0' 
AND `s`.`concept` = '0' 
AND `s`.`subscription` = '0' 
AND (`total_price_incl_tax` <> (SELECT SUM(`amount`) AS sum FROM `invoice_payments` WHERE `invoice_id` = s.id AND invoice_type = 'sales') OR (SELECT SUM(amount) AS sum FROM `invoice_payments` WHERE `invoice_id` = s.id AND invoice_type = 'sales') IS NULL)

你知道怎么做吗？

只需封装：

SELECT
  count(*),
  SUM(total_price_incl_tax),
  SUM(paid)
FROM
(
   SELECT 
   total_price_incl_tax,
   (SELECT SUM(amount) AS total FROM `invoice_payments` WHERE `invoice_id` = s.id AND invoice_type = 'sales') as paid
   FROM sales_invoices AS s 
   WHERE s.administration_id = 10605 
   AND `s`.`delete` = '0' 
   AND `s`.`concept` = '0' 
   AND `s`.`subscription` = '0' 
   AND (`total_price_incl_tax` <> (SELECT SUM(`amount`) AS sum FROM `invoice_payments` WHERE `invoice_id` = s.id AND invoice_type = 'sales') OR (SELECT SUM(amount) AS sum FROM `invoice_payments` WHERE `invoice_id` = s.id AND invoice_type = 'sales') IS NULL)
) t

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谢谢你的解决方案