Mysql 选择某些行的计数作为列

我有一个带有“status”列的表，它接受一个

TINYINT

。例如：

name   | status
-------+--------
john   | 0
joe    | 1
johann | 0
jan    | 1
jane   | 0

如何获得状态1和状态0的计数

status1 | status0
--------+--------
2       | 3

---

只需使用条件聚合：

select sum(status = 1) as status1, sum(status = 0) as status0
from t;

在您的情况下，您也可以这样写：

select sum(status) as status1, sum(1 - status) as status0
from t;

---

只需使用条件聚合：

select sum(status = 1) as status1, sum(status = 0) as status0
from t;

在您的情况下，您也可以这样写：

select sum(status) as status1, sum(1 - status) as status0
from t;

---

我会用一个案例陈述来检查你的价值

SELECT SUM(CASE WHEN [status] = 1 THEN 1 ELSE 0 END) AS Status1,
    SUM(CASE WHEN [status] = 0 THEN 1 ELSE 0 END) AS Status0
FROM tbl;

---

我会用一个案例陈述来检查你的价值

SELECT SUM(CASE WHEN [status] = 1 THEN 1 ELSE 0 END) AS Status1,
    SUM(CASE WHEN [status] = 0 THEN 1 ELSE 0 END) AS Status0
FROM tbl;