在MYSQL中如何根据时间间隔将行转换为列

我有如下示例数据：

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

如何获得如下输出：

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

        ID Val   Name        o_Dt                 o_gate      c_Dt             c_gate
        1, 145, 'Test1', '2020-01-28 02:18:00', 'open'        NULL               NULL
        2, 145, 'Test2', '2020-01-28 04:10:00', 'open'        NULL               NULL
        3, 145, 'Test3', '2020-01-28 05:50:00', 'open'  '2020-01-28 05:56:00', 'close'
        4, 145, 'Test4', '2020-01-28 07:36:00', 'open'  '2020-01-28 07:47:00', 'close'

我尝试过不同的场景，但没有前进 使用

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

按dt排序的合并状态

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

没有得到确切的结果。有谁能对此提出建议吗

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

以前我问过相同数据集的问题，但现在要求改变了

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

链接： 一种方法使用滞后：

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

编辑：

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

调整后的数据

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

您可以只使用条件聚合：

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

select val, name,
       min(case when status = 'open' then status end) as o_gate,
       min(case when status = 'open' then dt end) as o_dt,
       max(case when status = 'close' then status end) as c_gate,
       max(case when status = 'close' then dt end) as c_dt,
from t
group by val, name;

他是一把小提琴

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

如果要重建id，可以使用以下表达式：

            ID Val   Name        Dt                 Status
            1, 145, 'Test1', '2020-01-28 02:18:00', 'open'
            2, 145, 'Test2', '2020-01-28 04:10:00', 'open'
            3, 145, 'Test3', '2020-01-28 05:50:00', 'open'
            4, 145, 'Test3', '2020-01-28 05:56:00', 'close'
            5, 145, 'Test4', '2020-01-28 07:36:00', 'open'
            6, 145, 'Test4', '2020-01-28 07:42:00', 'open'
            7, 145, 'Test4', '2020-01-28 07:44:00', 'open'
            8, 145, 'Test4', '2020-01-28 07:47:00', 'close'

row_number() over (order by min(dt)) as id

---

但这一条不会给出打开日期和关闭日期@Gordon LinoffI已经尝试了条件聚合，但当我在select语句中添加其他列时，它不起作用。@mohan111。这回答了您在这里提出的问题。如果你有一个不同的问题，问一个新问题。对于相同的列，它本身没有给出确切的结果，它是在name@gordon上分组，它没有给出确切的结果result@mohan111 . . . 我加了一把小提琴。这将完全返回您指定的结果。你的问题已经回答了。如果你有一个不同的问题，把它当作一个新问题来问。结束约会的逻辑对我来说没有意义。原始数据中只有一行带有“close”（关闭），但不知何故您将其转换为两个关闭日期。抱歉@GordonLinoff我已修改了输入数据。请现在查看