如何在mysql中选择字段

我有一个带有jscode的select选项

示例jscode

$(selector).append($("<option/>", { value: "test", text: "Test123"}));

调用存储过程时，输出的是列名“test”，而不是“test”中columnname的值5413

我正在为框架使用codeigniter

数据库示例

|test|-columnname 
|5413|-data

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您需要动态地构造SQL

SET @stmt = CONCAT('SELECT `', p_test, '` FROM example_db WHERE Id = ?');
PREPARE stmt FROM @stmt;
EXECUTE stmt USING p_Id;

SET @stmt = CONCAT('SELECT `', p_test, '` FROM example_db WHERE Id = ?');
PREPARE stmt FROM @stmt;
EXECUTE stmt USING p_Id;