Mysql SQL多对多

我这里有五个表格：

使用者

受试者id

+------------+--------------+
| subject_id | subject_name |
+------------+--------------+
|          1 | mathematics  |
|          2 | science      |
|          3 | english      |
+------------+--------------+

批处理

主题组

+----------+------------+
| batch_id | subject_id |
+----------+------------+
|        1 |          1 |
|        1 |          2 |
|        1 |          3 |
|          |            |
+----------+------------+

科目评估

+--------+----------+
| stu_id | batch_id |
+--------+----------+
|      1 |        1 |
+--------+----------+

我试图实现的选择是

+--------+----------+------------+--------------+
| stu_id | batch_id | subject_id | subject_name |
+--------+----------+------------+--------------+
|      1 |        1 |          1 | mathematics  |
|      1 |        1 |          2 | science      |
|      1 |        1 |          3 | english      |
|        |          |            |              |
+--------+----------+------------+--------------+

我试过了=

$query = "SELECT subject.subject_name, user.first_name, batch.batch_name 
from subject_assessment inner join user 
ON subject_assessment.student_id = user.user_id inner 
join batch ON subject_assessment.batch_id = batch.batch_id  
left join subject_batch on = subject.subject_name = subject_batch.subject_id";

但是失败了。当我移除

subject.subject_name 

及

但这样我就无法检索主题id和主题名称

---

感谢您的帮助。提前谢谢您。

以下是它的外观：

select user.stu_id, user.batch_id, subject.subject_id, subject.subject_name
from user 
inner join subject_batch on user.batch_id = subject_batch.batch_id 
inner join subject on subject.subject_id = subject_batch.subject_id
order by user.stu_id;

这里是您可以运行它的地方：

---

请改进表格的格式，现在无法查看数据。抱歉，给您带来麻烦谢谢，我能够进行编码并获取特定数据。非常感谢你。

subject.subject_name 

left join left join subject_batch on = subject.subject_name = subject_batch.subject_id"

select user.stu_id, user.batch_id, subject.subject_id, subject.subject_name
from user 
inner join subject_batch on user.batch_id = subject_batch.batch_id 
inner join subject on subject.subject_id = subject_batch.subject_id
order by user.stu_id;