MySQL一条更新语句（+；）=

这是一条oracle语句，我无法在mySQL中运行此连接

update dept x
set totsal = (select sum(nvl(sal,0))
from emp e,dept d
where e.deptno(+) = d.deptno
and x.deptno = e.deptno);

输出应该是

Deptno    Dname      Loc      Totsal

10    ACCOUNTING  NEW YORK    8750
20    RESEARCH     DALLAS    10875
30    SALES     CHICAGO    9400
40    OPERATIONS  BOSTON    0

    update dept x
    INNER JOIN (
    select d.deptno, sum(ifnull(e.sal,0)) totsal
    from dept  d
    left join emp  e  ON  e.deptno = d.deptno
    GROUP BY d.deptno
    ) t on t.deptno = x.deptno
    set x.totsal = t.totsal

在mysql中应该是

Deptno    Dname      Loc      Totsal

10    ACCOUNTING  NEW YORK    8750
20    RESEARCH     DALLAS    10875
30    SALES     CHICAGO    9400
40    OPERATIONS  BOSTON    0

    update dept x
    INNER JOIN (
    select d.deptno, sum(ifnull(e.sal,0)) totsal
    from dept  d
    left join emp  e  ON  e.deptno = d.deptno
    GROUP BY d.deptno
    ) t on t.deptno = x.deptno
    set x.totsal = t.totsal

---

您试图在MySql中对

（+）

使用过时的联接语法。

相反，您应该将

dept

加入此查询：

select deptno, sum(sal) totsal
from emp
group by deptno

返回每个部门的总工资：

update dept d
left join (
  select deptno, sum(sal) totsal
  from emp
  group by deptno
) e on e.deptno = d.deptno
set d.totsal = coalesce(e.totsal, 0)

但我相信这是比较简单的：

update dept d
set d.totsal = coalesce((select sum(e.sal) from emp e where e.deptno = d.deptno), 0);

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非常感谢这解决了问题（打字错误：x.deptno）@EA90 type更正。。如果我的答案是正确的，请（过去15分钟）将其标记为已接受…看这里如何感谢我接受了答案非常感谢，这真的很有帮助