Mysql （SQL）如何将count（）放入已存在的列中？

在下一段代码中，我显示了count as coin的别名，但我想将其放入结果中名为matches的列中，希望有人能帮助我

候选表中已存在“新列匹配项”，我想用计数值填充它

SQL代码：

SELECT table1.* , count(*) as coin from (
(SELECT c.* from jobweb.candidates c, jobweb.additional_knowledge ak where
(ak.candidate_id = c.candidate_id) and (ak.knowledge like '%ccna%' or 
ak.knowledge_description like '%ccna%' or 
ak.knowledge like '%java%' or ak.knowledge_description like '%java%'))
union all
(SELECT c.* from jobweb.candidates c , jobweb.work_experience we where 
( we.candidate_id = c.candidate_id ) and
( we.position_name like '%sdh%' or we.functions_desciption like '%sdh%' or 
we.position_name like '%sharepoint%' or we.functions_desciption like '%sharepoint%' or 
we.position_name like '%proyecto%' or we.functions_desciption like '%proyecto%' or 
we.position_name like '%ingeniero%' or we.functions_desciption like '%ingeniero%' ))
union all
(SELECT c.* from jobweb.candidates c, jobweb.formal_education fe where
(fe.candidate_id =  c.candidate_id and fe.education_description like '%ingeniero%'))
)  as table1 group by table1.candidate_id order by coin desc

解决方案： 我放弃使用SQL来提取列匹配项上的值，因此我使用hibernate来执行此操作：

public List<Candidate> getCandidatesMatchesNativeSQL(String customQuery) {
    Query query = sessionFactory.getCurrentSession().createSQLQuery(customQuery)
            .addEntity(Candidate.class)
            .addScalar("matchCounter");
    @SuppressWarnings("unchecked")
    List<Object[]> objects = query.list();
    List<Candidate> candidates = new ArrayList<Candidate>();
    for (Object[] object : objects ) {
        Candidate candidate = (Candidate) object[0];
        BigInteger match = (BigInteger) object[1];
        candidate.setMatches( match.intValue() );
        candidates.add(candidate);
    }
    return candidates;
}

---

刚把硬币换成了“选择和排序”中的匹配项

       CREATE TEMPORARY TABLE IF NOT EXISTS table2 AS 
   (SELECT table1.candidate_id , count(*) as coin   from (
    (SELECT c.* from jobweb.candidates c, jobweb.additional_knowledge ak where
    (ak.candidate_id = c.candidate_id) and (ak.knowledge like '%ccna%' or 
    ak.knowledge_description like '%ccna%' or 
    ak.knowledge like '%java%' or ak.knowledge_description like '%java%'))
    union all
    (SELECT c.* from jobweb.candidates c , jobweb.work_experience we where 
    ( we.candidate_id = c.candidate_id ) and
    ( we.position_name like '%sdh%' or we.functions_desciption like '%sdh%' or 
    we.position_name like '%sharepoint%' or we.functions_desciption like '%sharepoint%' or 
    we.position_name like '%proyecto%' or we.functions_desciption like '%proyecto%' or 
    we.position_name like '%ingeniero%' or we.functions_desciption like '%ingeniero%' ))
    union all
    (SELECT c.* from jobweb.candidates c, jobweb.formal_education fe where
    (fe.candidate_id =  c.candidate_id and fe.education_description like '%ingeniero%'))
    )  as table1 group by table1.candidate_id order by coin desc)

    Update A set A.matches=B.coin from 
    candidates A inner join table2 B on A.candidate_id=B.candidate_id

---

您使用的是哪种数据库管理系统？博士后？火鸟？Oracle？很抱歉我忘了，是MySQLI吗？很抱歉我不是很明确，新的列匹配项“已存在于候选表中，我想用count填充它values@DavilaR检查上面的查询，让我知道这是否有效。这里更新查询应该是您的匹配列table@Raja：简短的解释会有帮助，您的答案看起来像是在“选择”对话框中编辑了别名简单的魔法是UPDATE语句，更大的魔法是into TEMP，这对我来说是新的，thx。我尝试了，但回答是：错误代码：1064。您的SQL语法有错误；检查与您的MySQL服务器版本对应的手册，了解在第行的“select c.*from jobweb.c，jobweb.additional_knowledge ak where ak.c”附近使用的正确语法2@RajaRajendraprasath我不知道sintaxis Temp是否正常，因为它使Temp之后的所有句子都变成灰色