Mysql 如何从同一列中选择满足2个要求的用户

我试图回答以下问题。我需要在曲目栏中选择同时听过曲目1和曲目2的用户。出于某种原因，我完全不知道如何做到这一点。

以下是其中一种方法：

SELECT user_id from TABLE_NAME 
WHERE track = 'track_1' AND 
           user_id IN 
           (SELECT user_id from TABLE_NAME where track = 'track_2');

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以下是其中一种方法：

SELECT user_id from TABLE_NAME 
WHERE track = 'track_1' AND 
           user_id IN 
           (SELECT user_id from TABLE_NAME where track = 'track_2');

---

如果只有两个，您也可以使用GROUP BY并拥有：

SELECT user_id
FROM t
GROUP BY user_id
HAVING COUNT(DISTINCT track) > 1

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如果只有两个，您也可以使用GROUP BY并拥有：

SELECT user_id
FROM t
GROUP BY user_id
HAVING COUNT(DISTINCT track) > 1

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可能比需要where exists子查询更简单

Select userID
from yourtable
where Track in ('Track 1','Track 2')
group by userid
having count(1) = 2

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可能比需要where exists子查询更简单

Select userID
from yourtable
where Track in ('Track 1','Track 2')
group by userid
having count(1) = 2

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您可以计算每个用户收听的相关曲目的数量：

SELECT   user_id
FROM     mytable
WHERE    track IN ('track_1', 'track_2')
GROUP BY user_id
HAVING   COUNT(DISTINCT track) = 2

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您可以计算每个用户收听的相关曲目的数量：

SELECT   user_id
FROM     mytable
WHERE    track IN ('track_1', 'track_2')
GROUP BY user_id
HAVING   COUNT(DISTINCT track) = 2

这样行吗

SELECT UserId
FROM YourTable
WHERE Track in ('track_1','track_2')
group by UserId
Having  count(distinct Track) > 1;

这样行吗

SELECT UserId
FROM YourTable
WHERE Track in ('track_1','track_2')
group by UserId
Having  count(distinct Track) > 1;

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谢谢另一个问题。如果我想知道每首歌的发行日期呢。我会使用min功能吗？谢谢！另一个问题。如果我想知道每首歌的发行日期呢。我会使用min函数吗？