从MySQL获取较新和较旧的帖子，但至少有一定数量

我有这样一个数据库：

+------------+-------------+
| listed     | data        |
+------------+-------------+
| 2013-01-01 | random text |
| 2013-01-02 | random text |
| 2013-01-03 | random text |
| 2013-01-05 | random text |
| 2013-01-06 | random text |
| 2013-01-07 | random text |
+------------+-------------+

在这种情况下，“数据”是一个笑话的标题。我想在当前笑话旁边列出旧笑话和新笑话。不是每天都有笑话。如果没有新的，我只想要旧的，反之亦然

因此：

我可以在两个查询中执行此操作，如果另一个查询没有返回任何内容，则至少会得到两个笑话：

SELECT * FROM jokes WHERE listed>'$date' ORDER BY listed ASC limit 2
SELECT * FROM jokes WHERE listed<'$date' ORDER BY listed DESC limit 2

从列出的笑话中选择*>“$date”按列出的ASC限额2排序
从列出的笑话中选择*点击这里。我已经发布了这个非常大的查询的解决方案。但是我认为有人可以减小它的大小

SELECT * FROM (SELECT 
   listed,DATA,@r2 := @r2 + 1 AS num
FROM 
  jokes,
  (SELECT @r2:=0) AS e) t WHERE FIND_IN_SET(num,(SELECT FOUND FROM (SELECT 
    listed,`data`,@rn := @rn + 1 AS number,
    IF(listed = '2013-01-07',#pass your date here
        IF(@rn = 1,CONCAT(2,',',3),
            IF(@rn = (SELECT COUNT(*) FROM jokes),CONCAT(@rn-1,',',@rn-2),CONCAT(@rn-1,',',@rn+1)))    ,-1) 
        AS `found`
FROM jokes,(SELECT @rn := 0 ) r

ORDER BY listed ) AS k  WHERE `found` != -1))>0

检查这里。我已经发布了那个非常大的查询的解决方案。但我认为有人可以减小它的大小

SELECT * FROM (SELECT 
   listed,DATA,@r2 := @r2 + 1 AS num
FROM 
  jokes,
  (SELECT @r2:=0) AS e) t WHERE FIND_IN_SET(num,(SELECT FOUND FROM (SELECT 
    listed,`data`,@rn := @rn + 1 AS number,
    IF(listed = '2013-01-07',#pass your date here
        IF(@rn = 1,CONCAT(2,',',3),
            IF(@rn = (SELECT COUNT(*) FROM jokes),CONCAT(@rn-1,',',@rn-2),CONCAT(@rn-1,',',@rn+1)))    ,-1) 
        AS `found`
FROM jokes,(SELECT @rn := 0 ) r

ORDER BY listed ) AS k  WHERE `found` != -1))>0

您建议的方式（可以用“联合”子查询重写为一个查询）很好。您建议的方式（可以用“联合”子查询重写为一个查询）很好。