MySQL：在选择算术-未知字段中使用别名

以下是我的选择：

SELECT 
  SUM(t.amount + c.designFeeValue) as cashReceived, 
  ROUND(SUM(i.value) * (m.percentOurs / 100)) as adValue,
  m.managementFee as managementFee,
  m.productionCost as productionCost,
  5 as emailAddress,
  (
    (
      SELECT value
      FROM commission_transactions
      WHERE isDebit IS
      TRUE
    ) -
    (
      SELECT value
      FROM commission_transactions
      WHERE isDebit IS
      FALSE
    )
  ) as miscExpenses,
  (managementFee + productionCost + emailAddress + miscExpenses) as totalExpenses

这是因为下面一行，我加了一些别名

(managementFee + productionCost + emailAddress + miscExpenses) as totalExpenses

别名是未知字段

有没有一种方法可以保留此算法的别名，或者我需要重新进行生成每个别名的所有数学运算以计算totalExpenses？这似乎是一种非常丑陋的方式

更新：

根据您的建议，我现在使用的是派生表

SELECT 
  cashReceived,
  adValue,
  managementFee,
  productionCost,
  emailAddress,
  miscExpenses,
  adValue + managementFee + productionCost + emailAddress + miscExpenses as totalExpenses
FROM (
  SELECT
    SUM(t.amount + c.designFeeValue) as cashReceived,
    ROUND(SUM(i.value) * (m.percentOurs / 100)) as adValue,
    m.managementFee as managementFee,
    m.productionCost as productionCost,
    5 as emailAddress,
    (
      (
        SELECT value
        FROM commission_transactions
        WHERE isDebit IS TRUE
      ) -
      (
        SELECT value
        FROM commission_transactions
        WHERE isDebit IS FALSE
      )
    ) as miscExpenses  
  FROM magazines m
  JOIN insertions i ON i.magazineId = m.id
  JOIN transactions t ON t.insertionId = i.id
  JOIN contracts c ON i.contractId = c.id
  JOIN commission_transactions ct ON m.id = ct.magazineId
  WHERE m.id = 17
    AND t.isChargedBack IS FALSE
    AND t.`timestamp` >= '2013-08-01 00:00:00'
    AND t.`timestamp` < '2013-09-01 00:00:00'
    AND ct.createdDate >= '2013-08-01 00:00:00'
    AND ct.createdDate < '2013-09-01 00:00:00'
) sub;

---

别名在字段列表中不可重复使用，例如：

mysql> select 5 as five, five + 1 as six;
ERROR 1054 (42S22): Unknown column 'five' in 'field list'

您必须用另一个包装器包装select，然后在该包装器中进行别名计算，例如

select *, managementFee + productionCost + emailAddress + miscExpenses) as totalExpenses
FROM (
   ... your above query here ...
)

---

尝试写出您的TableAlias.yourColumnAlias，如果这不起作用，请重新计算。类似于miscexpenses.managementFree+miscexpenses.ProductionCost这个分号：“2013-09-01 00:00:00”；在你的各种约会结束时，你不应该在那里；是语句终止符，但此时您尚未完成查询，至少有一个问题尚未解决。还有一个问题。。。奇怪的是，cashceived、adValue和totalExpenses都是空的。这些字段在sub中是通过算术生成的。如何访问外部SELECT中的这些字段？基本上，外部/包装器查询将内部查询视为一个表。只要外部使用的别名/字段名与内部查询使用的别名/字段名完全相同，您就应该返回数据。当我使用*或sub.cashReceived时会发生同样的情况。如果外部查询中的别名/字段名为null，则内部查询中的别名/字段名也会返回null。