mysql图表子查询

我有两个表，其中包含以下数据

可邀请的

inviteDate  | contractAmount | status

2014-01-01     1500             awarded
2015-01-01     2000             awarded
2015-01-02     4000             closed
2015-02-01     6000             awarded
2015-02-02     8000             awarded
2015-03-01     8500             awarded

可引用

quoteDate  | quoteAmount | status

2014-03-01     1500         awarded
2015-01-02     2000         awarded
2015-01-03     4000         sent
2015-01-04     6000         awarded
2015-02-03     8000         awarded
2015-02-10     8500         sent
2015-02-11     9000         awarded
2015-03-01     9500         awarded

我想进行一个查询，该查询提供以下数据结构

month   | quotedTotal | quotedCount | awardedTotal | awardedCount

January      8000           2             2000            1
February    17000           2            14000            2
March        9500           1             8500            1

目前我已经写了这段代码…但它不起作用

  SELECT
    MONTHNAME(t1.due_date) as month,
    (select sum(`amount`) from quoteTable where awarded= 1 ) as estimatedAmount,    
     sum(t1.contactAmount) AS sumContactAmount,
     COUNT(*) as `noOfAwarded`

    FROM inviteTable t1 

    where

    t1.status = "Awarded" and 
    t1.inviteDate between '2014-11-01' and '2015-10-31'

 GROUP BY MONTH(due_date)
    ;

基本上，我希望有一个查询，该查询提供以下信息：

获得奖励的数量-合同金额和授予状态的总和

已授予的数量计数-可邀请的计数。状态=已授予

获得报价的数量-报价数量和授予状态的总和

报价数量计数-报价表计数。状态=已授予

按月份和日期范围进行分组

---

我的查询不起作用。我被困住了，非常感谢你的帮助

这是一种方法，请注意，两个表中都有日期，最好使用join

left join

，这样可以确保在这种情况下，左表中的日期始终返回月份名称

select
t1.month,
t1.awardedTotal,
t1.awardedCount,
t2.quotedTotal,
t2.quotedCount 
from(
  select
  monthname(t1.inviteDate) as month,
  month(t1.inviteDate) as m,
  sum( 
    case 
     when t1.status = 'awarded' then t1.contractAmount else 0
    end
  ) as awardedTotal,
  sum( 
    case 
     when t1.status = 'awarded' then 1 else 0
    end
  ) as awardedCount
  from inviteTable t1 
  where t1.inviteDate between '2014-11-01' and '2015-10-31'
  group by month 
)t1 
left join(
  select
  monthname(t2.quoteDate) as month,
  sum( 
    case 
     when t2.status = 'awarded' then t2.quoteAmount else 0
    end
  ) as quotedTotal,
  sum( 
    case 
     when t2.status = 'awarded' then 1 else 0
    end
  ) as quotedCount
  from quoteTable t2 
  where t2.quoteDate between '2014-11-01' and '2015-10-31'
  group by month
)t2 on
t1.month = t2.month
order by t1.m

更新： 是的，因为您希望两个表中存在日期，所以不能用上述过程完成，因为它总是将一个表视为左表，并从表中获取所有日期。要获取两个表中所有日期的数据，首先需要从两个表中获取日期，然后使用left join获取计算部分

select
t1.month,
coalesce(t2.awardedTotal,0) as awardedTotal,
coalesce(t2.awardedCount,0) as awardedCount,
coalesce(t3.quotedTotal,0) as quotedTotal,
coalesce(t3.quotedCount,0) as quotedCount
from(
  select month(inviteDate) as m,monthname(inviteDate) as month 
  from inviteTable where inviteDate between '2014-11-01' and '2015-10-31'
  union
  select month(quoteDate) as m,monthname(quoteDate) as month
  from quoteTable where quoteDate between '2014-11-01' and '2015-10-31'
)t1
left join(
  select
  monthname(inviteDate) as month,
  sum( 
    case 
     when status = 'awarded' then contractAmount else 0
    end
  ) as awardedTotal,
  sum( 
    case 
     when status = 'awarded' then 1 else 0
    end
  ) as awardedCount
  from inviteTable 
  group by month 
)t2 on t1.month = t2.month
left join(
  select
  monthname(quoteDate) as month,
  sum( 
    case 
     when status = 'awarded' then quoteAmount else 0
    end
  ) as quotedTotal,
  sum( 
    case 
     when status = 'awarded' then 1 else 0
    end
  ) as quotedCount
  from quoteTable 
  group by month
)t3 on t1.month=t3.month
order by t1.m

---

这里是一种方法，请注意，两个表中都有日期，最好使用join

左join

，这样可以确保在这种情况下，左表中的日期始终返回月份名称

select
t1.month,
t1.awardedTotal,
t1.awardedCount,
t2.quotedTotal,
t2.quotedCount 
from(
  select
  monthname(t1.inviteDate) as month,
  month(t1.inviteDate) as m,
  sum( 
    case 
     when t1.status = 'awarded' then t1.contractAmount else 0
    end
  ) as awardedTotal,
  sum( 
    case 
     when t1.status = 'awarded' then 1 else 0
    end
  ) as awardedCount
  from inviteTable t1 
  where t1.inviteDate between '2014-11-01' and '2015-10-31'
  group by month 
)t1 
left join(
  select
  monthname(t2.quoteDate) as month,
  sum( 
    case 
     when t2.status = 'awarded' then t2.quoteAmount else 0
    end
  ) as quotedTotal,
  sum( 
    case 
     when t2.status = 'awarded' then 1 else 0
    end
  ) as quotedCount
  from quoteTable t2 
  where t2.quoteDate between '2014-11-01' and '2015-10-31'
  group by month
)t2 on
t1.month = t2.month
order by t1.m

更新： 是的，因为您希望两个表中存在日期，所以不能用上述过程完成，因为它总是将一个表视为左表，并从表中获取所有日期。要获取两个表中所有日期的数据，首先需要从两个表中获取日期，然后使用left join获取计算部分

select
t1.month,
coalesce(t2.awardedTotal,0) as awardedTotal,
coalesce(t2.awardedCount,0) as awardedCount,
coalesce(t3.quotedTotal,0) as quotedTotal,
coalesce(t3.quotedCount,0) as quotedCount
from(
  select month(inviteDate) as m,monthname(inviteDate) as month 
  from inviteTable where inviteDate between '2014-11-01' and '2015-10-31'
  union
  select month(quoteDate) as m,monthname(quoteDate) as month
  from quoteTable where quoteDate between '2014-11-01' and '2015-10-31'
)t1
left join(
  select
  monthname(inviteDate) as month,
  sum( 
    case 
     when status = 'awarded' then contractAmount else 0
    end
  ) as awardedTotal,
  sum( 
    case 
     when status = 'awarded' then 1 else 0
    end
  ) as awardedCount
  from inviteTable 
  group by month 
)t2 on t1.month = t2.month
left join(
  select
  monthname(quoteDate) as month,
  sum( 
    case 
     when status = 'awarded' then quoteAmount else 0
    end
  ) as quotedTotal,
  sum( 
    case 
     when status = 'awarded' then 1 else 0
    end
  ) as quotedCount
  from quoteTable 
  group by month
)t3 on t1.month=t3.month
order by t1.m

---

你的模式很不幸；如果您只有一个表和一个额外的列来记录您所拥有的记录类型，那么就更容易了。但是，如果首先通过

union all

将两个表收集到一个表中，则可以使用相当简单的查询生成所需的结果：

select
  monthname(_date) month,
  sum(quoteAwarded * amount) quotedTotal,
  sum(quoteAwarded) quotedCount,
  sum(contractAwarded * amount) awardedTotal,
  sum(contractAwarded) awardedCount
from (select inviteDate _date, contractAmount amount, status = 'awarded' contractAwarded, 0 quoteAwarded from inviteTable
  union all
  select quoteDate, quoteAmount, 0, status = 'awarded' from quoteTable) x
where _date between '2014-11-01' and '2015-10-31'
group by 1
order by month(_date)

请参见使用示例数据和生成预期输出

---

这个查询的核心是一个方便的事实，（在mysql中）“true”是1，“false”是0-允许使用

sum（）

而不是

count（）

，更重要的是，通过在一些简单的数学上使用

sum（）

避免使用

case

；如果您只有一个表和一个额外的列来记录您所拥有的记录类型，那么就更容易了。但是，如果首先通过

union all

将两个表收集到一个表中，则可以使用相当简单的查询生成所需的结果：

select
  monthname(_date) month,
  sum(quoteAwarded * amount) quotedTotal,
  sum(quoteAwarded) quotedCount,
  sum(contractAwarded * amount) awardedTotal,
  sum(contractAwarded) awardedCount
from (select inviteDate _date, contractAmount amount, status = 'awarded' contractAwarded, 0 quoteAwarded from inviteTable
  union all
  select quoteDate, quoteAmount, 0, status = 'awarded' from quoteTable) x
where _date between '2014-11-01' and '2015-10-31'
group by 1
order by month(_date)

请参见使用示例数据和生成预期输出

---

这个查询的核心是一个方便的事实，（在mysql中）“true”是1，“false”是0-允许使用

sum（）

而不是

count（）

，更重要的是通过使用

sum（）避免使用
case

跳过一些简单的数学。

请提供

fiddle

链接来表示您的表和数据，这可以帮助每个人轻松找到解决方案。@user2062455您正在寻找，尽管您还应该提到它是如何工作的。另一个问题是，结果必须与两个表匹配或不匹配。例如，对于

一月
是否可能只有一个表有记录。请提供
fiddle
链接来表示您的表和数据，这可以帮助每个人轻松找到解决方案。@user2062455，尽管您还应该提到它是如何不起作用的。另一个问题是，结果必须与两个表匹配或不匹配。例如，对于
一月
是否可能只有一个表有记录。如果一个表中只有月份的日期，则这不起作用。看看exmaple：我应该说得更清楚一点。我正试图得到一份所有月份的列表，以及相应月份中的awardedTotal、awardedCount、quotedTotal、quotedCount的数据months@user2062455是如果需要表中的所有日期，则需要修改查询，检查更新的答案。如果一个表中只有月份的日期，则此操作无效。看看exmaple：我应该说得更清楚一点。我正试图得到一份所有月份的列表，以及相应月份中的awardedTotal、awardedCount、quotedTotal、quotedCount的数据months@user2062455是如果您需要表中的所有日期，那么您需要修改查询，请检查更新的答案。很遗憾，我无法将所有数据放在一个表中。你的解决方案很有魅力。Abhik的更新同样有效，但你的代码更少。谢谢你们两位的输入不幸的是，我不能把所有的数据都放在一个表中。你的解决方案很有魅力。Abhik的更新同样有效，但你的代码更少。谢谢你们两位的意见