Mysql SQL查询以获取上次语句连接相等的客户端数 我需要做一个SQL查询

表“记录”结构：

contact_id(integer), 
client_id(integer), 
worker_id(integer), 
statement_status(varchar), 
contact_ts(timestamp)

它必须显示以下内容：

current date
number of clients which last statement_status was 'interested'
number of clients which last statement_status was 'not_interested' and previus status was 'not_present'

有人能帮忙吗

样本数据：

contact_id  client_id   contact_ts                worker_id statement_status
'1',    '181',      '2017-09-24 03:38:31.000000', '107',    'voicemail'
'2',    '72',       '2017-09-23 09:32:38.000000', '10',     'not_interested'
'3',    '277',      '2017-09-22 07:06:16.000000', '119',    'interested'
'4',    '36',       '2017-09-21 04:39:57.000000', '118',    'not_present'
'5',    '33',       '2017-09-20 04:12:12.000000', '161',    'voicemail'
'6',    '244',      '2017-09-19 02:26:30.000000', '13',     'not_interested'
'7',    '346',      '2017-09-18 02:30:35.000000', '255',    'interested'
'8',    '128',      '2017-09-17 06:20:13.000000', '52',     'not_present'
'9',    '33',       '2017-09-16 08:58:02.000000', '188',    'not_present'
'10',   '352',      '2017-09-15 08:18:40.000000', '324',    'not_interested'
'11',   '334',      '2017-09-14 04:27:40.000000', '373',    'interested'
'12',   '2',        '2017-09-13 08:44:40.000000', '40',     'not_present'
'13',   '33',       '2017-09-12 03:46:16.000000', '252',    'voicemail'
'14',   '366',      '2017-09-11 04:31:22.000000', '78',     'not_interested'
'15',   '184',      '2017-09-10 06:08:01.000000', '289',    'interested'
'16',   '184',      '2017-09-09 05:45:56.000000', '124',    'not_present'
'17',   '102',      '2017-09-08 07:09:30.000000', '215',    'voicemail'
'18',   '140',      '2017-09-07 08:09:18.000000', '196',    'not_interested'
'19',   '315',      '2017-09-06 05:13:40.000000', '242',    'interested'
'20',   '268',      '2017-09-05 07:41:40.000000', '351',    'not_present'
'21',   '89',       '2017-09-04 05:32:05.000000', '232',    'voicemail'

期望输出：

我尝试了一些子查询，但显然不起作用：

SELECT 
GETDATE()
,(select count(*) 
            from record a 
            where (select statement_status 
                   from record
                   where client_id == a.client_id
                   order by a.contact_ts
                   limit 1) == "interested"
                   group by a.contact_id)
            
,(select count(*) 
            from record a 
            where (select (select statement_status 
                   from record
                   where client_id == a.client_id
                   order by a.contact_ts
                   limit 2) order by a.contact_ts desc limit 1) == "interested"
                   and
                   (select statement_status 
                   from record
                   where client_id == a.client_id
                   order by a.contact_ts
                   limit 1) == "interested"
                   
                   group by a.contact_id)
            
from record b;

我应该如何使用内部选择？ 我必须写一首诗，因为我的大部分帖子都是代码。 也许是死人的东西

“不要让太阳在你屁股上烧个洞，威廉·布莱克。现在起来，开你的车，在死人的骨头上犁地！”

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)

试试这样的方法：

身份为 选择不同的客户端id， w1上的第一个状态作为最后一个状态， 第n个值声明状态，2比w1为上一个状态 根据记录 窗口w1作为按客户id划分的分区按联系人顺序描述无界前向和无界后向之间的范围 选择当前日期， SUMlast_状态=“感兴趣”为感兴趣， SUMlast_status='not_interest'和prev_status='not_present'为not_interest 来自身份

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请显示示例数据和预期输出，以及您尝试过的内容，并在CTE中读取每个客户端的枚举行，在查询中查找相应行，然后应用条件聚合。您使用的是哪个版本的mysql？也许您可以使用窗口函数来捕获以前状态的案例。如果你正在准备一个简单的例子，请放一些可以直接运行的sql代码。我想这是我想要的最新版本。唐克斯兄弟。

SELECT 
GETDATE()
,(select count(*) 
            from record a 
            where (select statement_status 
                   from record
                   where client_id == a.client_id
                   order by a.contact_ts
                   limit 1) == "interested"
                   group by a.contact_id)
            
,(select count(*) 
            from record a 
            where (select (select statement_status 
                   from record
                   where client_id == a.client_id
                   order by a.contact_ts
                   limit 2) order by a.contact_ts desc limit 1) == "interested"
                   and
                   (select statement_status 
                   from record
                   where client_id == a.client_id
                   order by a.contact_ts
                   limit 1) == "interested"
                   
                   group by a.contact_id)
            
from record b;