MySql连接两个表和左表的错误结果

我有一个两个表，我离开了join，想要两个表的值之和。
但未成功检索第二个表的结果（SUM未正确分组）
表test1

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

表test2

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

输出

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

camp_id redeem  cost    bill    earning
1       5       1500    15000   165
2       4       5000    NULL    NULL
3       2       1200    NULL    NULL

camp_id redeem  cost    bill    earning
1       5       1500    4000    50
2       4       5000    11000   115
3       2       1200    0       0

期望的结果

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

camp_id redeem  cost    bill    earning
1       5       1500    15000   165
2       4       5000    NULL    NULL
3       2       1200    NULL    NULL

camp_id redeem  cost    bill    earning
1       5       1500    4000    50
2       4       5000    11000   115
3       2       1200    0       0

我已经执行了以下SQL

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

SELECT
t1.camp_id,
t1.redeem,
t1.cost,
t2.bill,
t2.earning
FROM (SELECT  COALESCE(SUM(redeem_count),0) AS redeem, COALESCE(SUM(cost),0) AS cost, id,camp_id FROM test1 GROUP BY camp_id) t1
LEFT JOIN(SELECT COALESCE(SUM(bill_amount),0) AS bill, COALESCE(SUM(earning),0) AS earning, test1_id FROM test2) t2
ON t1.id = t2.test1_id

我如何才能达到预期的结果？请您提供解决方案好吗

试试这个：

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

SELECT
t1.camp_id,
t1.redeem,
t1.cost,
t2.bill,
t2.earning
FROM (SELECT  COALESCE(SUM(redeem_count),0) AS redeem, COALESCE(SUM(cost),0) AS cost, id,camp_id FROM test1 GROUP BY camp_id) t1
LEFT JOIN(SELECT COALESCE(bill_amount) AS bill, COALESCE(earning) AS earning, test1_id FROM test2) t2
ON t1.id = t2.test1_id

更新：1

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

SELECT
t1.camp_id,
t1.redeem,
t1.cost,
t2.bill,
t2.earning
FROM 
(
SELECT  
COALESCE(SUM(redeem_count),0) AS redeem, 
COALESCE(SUM(cost),0) AS cost, 
id,
camp_id 
FROM test1 
GROUP BY camp_id) t1
LEFT JOIN(
SELECT 
SUM(bill_amount) AS bill, 
SUM(earning) AS earning, test1_id FROM test2 GROUP BY test1_id) t2
ON t1.camp_id= t2.test1_id

我的代码生成了如下输出：

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

camp_id redeem  cost    bill     earning
1       5       1500    4000     50
2       4       5000    11000    115
3       2       1200    (NULL)   (NULL)

---

已编辑

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

创建子查询，就像只查询所需结果一样，然后连接这些结果

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

（未测试查询！）

id  redeem_count        cost   camp_id
1   2                   500    1
2   3                   1000   1
3   2                   2000   2
4   2                   3000   2
5   2                   1200   3

id  bill_amount     earning test1_id
1   4000            50      1
2   5000            55      3
3   6000            60      4

---

您是否正在处理@jmail-answer的粘贴（同一问题）请参阅评论检查我的

更新：1

回答和输出，问题是如果您不提及

test1\u id=3的账单金额和收入的值，那么只有它产生
空值
。是的，我不想按test1\u id添加组…这会有问题，先生。。。意味着test1\u id只是外键…请现在查看表2（test2）（问题更新）。我不想在左边的桌子上分组……是的，我看到了。事实上，这不是一个“想要还是不想要”的问题。你问了如何做，想要的输出需要GROUPBY子句。请看test2表…我有值changedOK，我现在明白了，对不起。编辑了我的回答，并将昏迷添加到
SUM（T2.bill）的末尾作为bill