Mysql 工作日（日期）与当前日期工作日比较

这个查询有什么问题。它给了我错误的结果

尝试如下：

SELECT 
  * 
FROM
  (`users`) 
  JOIN `artistprofiles` AS art 
    ON `art`.`user_id` = `users`.`id` 
WHERE WEEKDAY(users.date_created) = 'WEEKDAY(WEEKDAY(NOW()))' 
  AND `users`.`status_enum` = 'aproved' 
  AND `users`.`status` = 1 
ORDER BY `users`.`email_process` DESC 

“

将其设置为字符串。所以你没有工作日

您可能想阅读以下内容：

这是错误的：

SELECT * FROM (`users`) JOIN `artistprofiles` AS art ON `art`.`user_id` = `users`.`id` WHERE WEEKDAY(users.date_created) = WEEKDAY(NOW()) AND `users`.`status_enum` = 'aproved' AND `users`.`status` = 1 ORDER BY `users`.`email_process` desc

示例：

WHERE WEEKDAY(users.date_created) = 'WEEKDAY(WEEKDAY(NOW()))' 

select 
    @wd:=WEEKDAY(curdate()) wd, 
    @str:='WEEKDAY(WEEKDAY(NOW()))' str, 
    @wd=@str,
    @wd=WEEKDAY( now() ) ;

结果：

WHERE WEEKDAY(users.date_created) = 'WEEKDAY(WEEKDAY(NOW()))' 

select 
    @wd:=WEEKDAY(curdate()) wd, 
    @str:='WEEKDAY(WEEKDAY(NOW()))' str, 
    @wd=@str,
    @wd=WEEKDAY( now() ) ;

在查询中，您将周值与文本字符串“WEEKDAY（WEEKDAY（NOW（））”进行比较。由于它们不匹配，它将返回false，因此您将看到错误的结果

若要检查列的周日是否为“现在的周日”，则

更改：

+------+-------------------------+----------+----------------------+
| wd   | str                     | @wd=@str | @wd=WEEKDAY( now() ) |
+------+-------------------------+----------+----------------------+
|    2 | WEEKDAY(WEEKDAY(NOW())) |        0 |                    1 |
+------+-------------------------+----------+----------------------+

WHERE WEEKDAY(users.date_created) = 'WEEKDAY(WEEKDAY(NOW()))' 

至：

+------+-------------------------+----------+----------------------+
| wd   | str                     | @wd=@str | @wd=WEEKDAY( now() ) |
+------+-------------------------+----------+----------------------+
|    2 | WEEKDAY(WEEKDAY(NOW())) |        0 |                    1 |
+------+-------------------------+----------+----------------------+

WHERE WEEKDAY(users.date_created) = 'WEEKDAY(WEEKDAY(NOW()))' 

---

试试这个

WEEKDAY（users.date_created）=WEEKDAY（NOW（））

没有一个引号。我正在用codeigniter编写它，它会自动将“”放在上面。我如何删除它