Mysql arm。这个错误消息的真正含义是什么，在什么情况下它会显示出来，以任何方式都可以确定吗？由于它发生在不涉及双精度值的上下文中，因此似乎有点误导。猜测它试图在和之前计算“secoll XVI-XVIII”的布尔值。如果您有“其中x='x'和y”你会发现这个构

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arm。这个错误消息的真正含义是什么，在什么情况下它会显示出来，以任何方式都可以确定吗？由于它发生在不涉及双精度值的上下文中，因此似乎有点误导。猜测它试图在和之前计算“secoll XVI-XVIII”的布尔值。如果您有“其中x='x'和y”你会发现这个构思拙劣、晦涩难懂的错误真的很高兴我在把电脑扔进墙之前找到了这个答案所以像我这样犯这个错误的人肯定是愚蠢的，“截断不正确的双精度值”是一条非常无用的警告消息……基本上，只要出现语法问题，它就会抛出这个无用的异常“mysql截断不正确的双精度值”是的。我也有过类似的经历，当时我试图在where子句中使用字符串文字，而不使用引号。我正因为这个而准备自杀。感谢上帝你救了我的命。这是愚蠢的和更新。为我工作+1:）您可以设置警告失败选项-查看是否包括内部尖叫失败？

UPDATE shop_category 
SET name = 'Secolul XVI - XVIII' 
    AND name_eng = '16th to 18th centuries' 
WHERE category_id = 4768

1292 - Truncated incorrect DOUBLE value: 'Secolul XVI - XVIII'

category_id   mediumint(8)
name        varchar(250)
name_eng      varchar(250)

UPDATE 
    shop_category 
SET 
    name = 'Secolul XVI - XVIII', 
    name_eng = '16th to 18th centuries' 
WHERE 
    category_id = 4768

UPDATE shop_category 
SET name = 'Secolul XVI - XVIII', name_eng = '16th to 18th centuries' 
WHERE category_id = 4768

update table set coulmn1='something' where column2 in (00012121);

INSERT INTO users (user_name) SELECT name FROM site_users WHERE
INSTR(status, 'active'>0);

INSERT INTO users (user_name) SELECT name FROM site_users WHERE
INSTR(status, 'active')>0;

insert into myTable (a, b, c)
values (
   123 --something
  ,345 --something else
  ,567 --something something else
);

UPDATE myTable SET myValue = NULL WHERE myValue = 0;

+---------+------+-----------------------------------------------+
| Level   | Code | Message                                       |
+---------+------+-----------------------------------------------+
| Warning | 1292 | Truncated incorrect DOUBLE value: 'value xyz' |
+---------+------+-----------------------------------------------+

UPDATE myTable SET myValue = NULL WHERE myValue = '0';
                                                  ^^^
                                                  Quotation here!

select * from shops where shop_id = 26244317283;

update stores set store_url = 'https://test-url.com' where shop_id = 26244317283;

update stores set store_url = 'https://test-url.com' where shop_id = '26244317283';

[...] AND EXISTS (select objectid from temp_objectids where temp_objectids.objectid = items_raw.objectid );

UPDATE `cdr` SET `userfield`='survey=5,' WHERE `uniqueid` = 1610386969.1713

UPDATE `cdr` SET `userfield`='survey=5,' WHERE `uniqueid` = '1610386969.1713'

UPDATE shop_category SET name = 'Secolul XVI - XVIII', name_eng = '16th to 18th centuries' WHERE category_id = 4768