Mysql 我在insert select上获得了不正确的日期值
我想执行插入选择,但在phpmyadmin中,我在第1行的“日期”列中不断收到错误#1292-不正确的日期值:“” 现在,select自动工作,没有错误。我只有在添加INSERT语句时才会出现错误,例如,这是可行的Mysql 我在insert select上获得了不正确的日期值,mysql,Mysql,我想执行插入选择,但在phpmyadmin中,我在第1行的“日期”列中不断收到错误#1292-不正确的日期值:“” 现在,select自动工作,没有错误。我只有在添加INSERT语句时才会出现错误,例如,这是可行的 SELECT `SalesInvoice_id`, `Date`, IFNULL(`valueOriginal`+`VATOriginal`,0) as `Amount` FROM (SELECT `salesinvoice`
SELECT
`SalesInvoice_id`,
`Date`,
IFNULL(`valueOriginal`+`VATOriginal`,0) as `Amount`
FROM
(SELECT
`salesinvoice`.`SalesInvoice_id`,
`DatePaid` AS `Date`,
ROUND(SUM((`Unit_Cost`*`Quantity`)),2) as `valueOriginal`,
IF(`salesinvoice`.`VAT`=2,ROUND(SUM(((`Unit_Cost`)*`Quantity`)/100*`salesinvoice_products`.`VAT`),2),0) as `VATOriginal`,
`InvoiceType`
FROM `salesinvoice`
LEFT JOIN `salesinvoice_products` ON `salesinvoice`.`SalesInvoice_id` = `salesinvoice_products`.`SalesInvoice_id`
GROUP BY `salesinvoice`.`SalesInvoice_id`
) a
WHERE `InvoiceType`!='3' && `Date`!=''
但当我这么做的时候
INSERT INTO `salesinvoice_payments` (`SalesInvoice_id`,`Date`,`Amount`)
SELECT
`SalesInvoice_id`,
`Date`,
IFNULL(`valueOriginal`+`VATOriginal`,0) as `Amount`
FROM
(SELECT
`salesinvoice`.`SalesInvoice_id`,
`DatePaid` AS `Date`,
ROUND(SUM((`Unit_Cost`*`Quantity`)),2) as `valueOriginal`,
IF(`salesinvoice`.`VAT`=2,ROUND(SUM(((`Unit_Cost`)*`Quantity`)/100*`salesinvoice_products`.`VAT`),2),0) as `VATOriginal`,
`InvoiceType`
FROM `salesinvoice`
LEFT JOIN `salesinvoice_products` ON `salesinvoice`.`SalesInvoice_id` = `salesinvoice_products`.`SalesInvoice_id`
GROUP BY `salesinvoice`.`SalesInvoice_id`
) a
WHERE `InvoiceType`!='3' && `Date`!=''
我得到了错误。好的,这是我的模式
DROP TABLE IF EXISTS salesinvoice_payments;
DROP TABLE IF EXISTS salesinvoice;
DROP TABLE IF EXISTS salesinvoice_products;
CREATE TABLE salesinvoice_payments
(`sipID` int(11) NOT NULL AUTO_INCREMENT,
`salesinvoice_id` int,
`Date` date,
`Amount` int,
PRIMARY KEY (`sipID`))
;
CREATE TABLE salesinvoice (
`SalesInvoice_id` int(11) NOT NULL AUTO_INCREMENT,
`VAT` tinyint(1) DEFAULT NULL,
`DatePaid` date DEFAULT NULL,
`InvoiceType` tinyint(1) DEFAULT 1,
PRIMARY KEY (`SalesInvoice_id`)
);
CREATE TABLE salesinvoice_products (
product_ID int(11) NOT NULL AUTO_INCREMENT,
SalesInvoice_id int(11) DEFAULT NULL,
Description varchar(255) DEFAULT NULL,
Unit_Cost decimal(19, 2) DEFAULT NULL,
Quantity int(11) DEFAULT NULL,
VAT decimal(10, 1) DEFAULT NULL,
PRIMARY KEY (product_ID)
);
INSERT INTO `salesinvoice`
(`SalesInvoice_id`,`VAT`, `DatePaid`, `InvoiceType`)
VALUES
(1,2,'2017-11-07',1),
(2,2,'2017-11-07',1),
(3,2,'2017-11-07',1),
(4,2,'2017-11-07',1),
(5,2,'2017-11-07',1),
(6,2,'2017-11-07',1)
;
INSERT INTO `salesinvoice_products`
(`SalesInvoice_id`, `Description`, `Unit_Cost`,`Quantity`,`VAT`)
VALUES
(3,'Sausage',1.50,5,21),
(3,'Cabbage',2.50,15,21),
(4,'Herring',2.50,15,21),
(4,'Red',2.50,15,21),
(3,'Dongle',2.50,15,21),
(2,'Thingy',2.50,15,21),
(2,'Spaceship',2.50,15,21),
(1,'Car',2.50,15,21),
(1,'Alien',2.50,15,21)
;
INSERT INTO `salesinvoice_payments` (`SalesInvoice_id`,`Date`,`Amount`)
SELECT
`SalesInvoice_id`,
`Date`,
IFNULL(`valueOriginal`+`VATOriginal`,0) as `Amount`
FROM
(SELECT
`salesinvoice`.`SalesInvoice_id`,
`DatePaid` AS `Date`,
ROUND(SUM((`Unit_Cost`*`Quantity`)),2) as `valueOriginal`,
IF(`salesinvoice`.`VAT`=2,ROUND(SUM(((`Unit_Cost`)*`Quantity`)/100*`salesinvoice_products`.`VAT`),2),0) as `VATOriginal`,
`InvoiceType`
FROM `salesinvoice`
LEFT JOIN `salesinvoice_products` ON `salesinvoice`.`SalesInvoice_id` = `salesinvoice_products`.`SalesInvoice_id`
GROUP BY `salesinvoice`.`SalesInvoice_id`
) a
WHERE `InvoiceType`!='3' && `Date`!=''
好的,这是我第一次发布关于堆栈溢出的帖子,我将展示我的SQLFIDLE。select insert在SQLFIDLE中工作正常,但在phpmyadmin中工作不正常。但是,在phpmyadmin中,我在第1行的“日期”列中得到一个错误#1292-不正确的日期值:“”。
由于某些原因,无法正确发送日期。选择时,您会收到相同的警告
mysql> SELECT ... WHERE `InvoiceType`!='3' && `Date`!='';
+-----------------+------------+--------+
| SalesInvoice_id | Date | Amount |
+-----------------+------------+--------+
| 1 | 2017-11-07 | 90.75 |
| 2 | 2017-11-07 | 90.75 |
| 3 | 2017-11-07 | 99.83 |
| 4 | 2017-11-07 | 90.75 |
| 5 | 2017-11-07 | 0.00 |
| 6 | 2017-11-07 | 0.00 |
+-----------------+------------+--------+
6 rows in set, 1 warning (0.01 sec)
mysql> show warnings;
+---------+------+-----------------------------------------------------+
| Level | Code | Message |
+---------+------+-----------------------------------------------------+
| Warning | 1292 | Incorrect date value: '' for column 'Date' at row 1 |
+---------+------+-----------------------------------------------------+
然而,当我们离开这个条件时,没有任何警告
mysql> SELECT ... WHERE `InvoiceType`!='3';
+-----------------+------------+--------+
| SalesInvoice_id | Date | Amount |
+-----------------+------------+--------+
| 1 | 2017-11-07 | 90.75 |
| 2 | 2017-11-07 | 90.75 |
| 3 | 2017-11-07 | 99.83 |
| 4 | 2017-11-07 | 90.75 |
| 5 | 2017-11-07 | 0.00 |
| 6 | 2017-11-07 | 0.00 |
+-----------------+------------+--------+
6 rows in set (0.01 sec)
因此,它抱怨的是将日期列与'
进行比较,而不是在表中插入值
将MySQL日期与''
进行比较是没有意义的。类型为DATE
或DATETIME
的列不能为空字符串。无效日期转换为0000-00-00,或者如果使用严格模式,则为错误。您永远无法获得''
的日期列
您可以得到一个NULL
的日期列。这可能就是你想要测试的NULL
和空字符串'
在标准SQL和MySQL中是不同的
我猜您有Oracle的经验,在许多上下文中,NULL
和空字符串被视为相同的(Oracle的这种行为不是标准的SQL)
我建议您在要筛选出NULL
时使用IS NOT NULL
mysql> SELECT ... WHERE `InvoiceType`!='3' AND `Date` IS NOT NULL;
+-----------------+------------+--------+
| SalesInvoice_id | Date | Amount |
+-----------------+------------+--------+
| 1 | 2017-11-07 | 90.75 |
| 2 | 2017-11-07 | 90.75 |
| 3 | 2017-11-07 | 99.83 |
| 4 | 2017-11-07 | 90.75 |
| 5 | 2017-11-07 | 0.00 |
| 6 | 2017-11-07 | 0.00 |
+-----------------+------------+--------+
6 rows in set (0.01 sec)
不确定,但其中一个是日期时间,另一个是日期。抱歉,日期时间是一个输入错误,现在把它放在
date
是一个糟糕的列名,重写它。我把它改为paymentDate,但仍然是相同的错误。它们起作用了。但我不明白的是。选择让我做,它给了我想要的结果。我只是在添加插入时失败了。正如我上面所示,我也得到了结果。但是它附带了一个警告,我必须使用SHOW WARNINGS
才能在MySQL客户端中看到它。警告的处理方式取决于您的设置(严格模式使警告的行为类似于错误)。每个客户端(例如phpmyadmin)对警告的反应也可能不同。我只是假设日期!=''因为日期存储为字符串,所以可以使用。我没有使用oracle的经验,但我使用了许多不同的语言,有时会把它们之间的语法搞砸。感谢BillDates在MySQL中不作为字符串存储。它们以更紧凑的二进制格式存储,即DATE
需要3个字节,DATETIME
需要8个字节。看见