MySQL连接和分组方式在同一个表上

下表列出了多个日期、品牌和市场

Date       | brand       | Market   |  CONV   | PgmGRPs     | 
-----------|-------------|----------|---------|-------------|
2020-01-01 | ABC         | MTL      | conv.   | 80          | 
2020-01-01 | ABC         | MTL      | Spec.   | 20          |
2020-01-01 | ABC         | TO       | conv.   | 70          |
2020-01-01 | ABC         | TO       | Spec.   | 40          |
2020-01-02 | DEF         | TO       | conv.   | 80          |
2020-01-02 | DEF         | TO       | Spec.   | 20          |
...

我想得到的是

 Date      |brand | Market |Conv. PgmGRPs |Spec. PgmGRPs |Total PgmGRPs |Conv. Ratio | Spec. Ratio|
-----------|------|--------|--------------|--------------|--------------|------------|------------|
2020-01-01 | ABC  | MTL    | 80           | 20           | 100          | 0.80       | 0.20       |
2020-01-01 | ABC  | TO     | 70           | 40           | 110          | 0.64       | 0.36       |
2020-01-02 | DEF  | TO     | 80           | 20           | 100          | 0.80       | 0.20       |
...

我尝试了以下方法，但没有成功

SELECT
a.`Brand`,
a.`PgmGRPs` as 'Conv. PgmGRPs',
b.`PgmGRPs` as 'Spec. PgmGRPs',
a.`PgmGRPs` + b.`PgmGRPs` AS 'Total PgmGRPs',
ROUND(a.`PgmGRPs`/ (a.`PgmGRPs` + b.`PgmGRPs`),2) as 'Conv. Ratio',
ROUND(b.`PgmGRPs`/ (a.`PgmGRPs` + b.`PgmGRPs`),2) as 'Spec. Ratio'

FROM 
(SELECT
`Brand`,
IF ( `CONV` = 'Conv.', SUM(`PgmGRPs`), 0)
 AS 'PgmGRPs'
FROM transform_data_1
GROUP BY `Brand`, `CONV`
) a

LEFT JOIN 
(SELECT
`Brand`,
`CONV`,
SUM(`PgmGRPs`) as 'PgmGRPs'
FROM transform_data_1
WHERE `CONV` = 'Spec.'
GROUP BY `Brand`, `CONV`
) b
ON a.`Brand` = b.`Brand`

这是我得到的，但我不知道如何获得日期、品牌、市场和删除第二行

    |brand | Market |Conv. PgmGRPs |Spec. PgmGRPs |Total PgmGRPs |Conv. Ratio | Spec. Ratio|
    |------|--------|--------------|--------------|--------------|------------|------------|
    | ABC  | MTL    | 80           | 20           | 100          | 0.80       | 0.20       |
    | ABC  | MTL    | 0            | 20           | 20           | 0          | 1.00       |
    ....

---

谢谢，

您得到双线的原因是第一个查询

SELECT
`Brand`,
IF ( `CONV` = 'Conv.', SUM(`PgmGRPs`), 0)
 AS 'PgmGRPs'
FROM transform_data_1
GROUP BY `Brand`, `CONV`

正在返回两行，并且您正在执行左外部联接，该联接将始终包含第一个查询中的每一行

相反，您应该像对第二个查询所做的那样，使用WHERE子句只获取第一个查询中的

Conv

行。然后做一个内部连接

SELECT
a.`Brand`,
a.`PgmGRPs` as 'Conv. PgmGRPs',
b.`PgmGRPs` as 'Spec. PgmGRPs',
a.`PgmGRPs` + b.`PgmGRPs` AS 'Total PgmGRPs',
ROUND(a.`PgmGRPs`/ (a.`PgmGRPs` + b.`PgmGRPs`),2) as 'Conv. Ratio',
ROUND(b.`PgmGRPs`/ (a.`PgmGRPs` + b.`PgmGRPs`),2) as 'Spec. Ratio'

FROM 
(SELECT
`Brand`,
SUM(`PgmGRPs`) AS 'PgmGRPs'
FROM transform_data_1
WHERE `CONV` = 'Conv.'
GROUP BY `Brand`
) a

INNER JOIN 
(SELECT
`Brand`,
`CONV`,
SUM(`PgmGRPs`) as 'PgmGRPs'
FROM transform_data_1
WHERE `CONV` = 'Spec.'
GROUP BY `Brand`, `CONV`
) b
ON a.`Brand` = b.`Brand`

---

这还允许我们从group by中删除

CONV

字段，我们不需要在select中对其进行测试。

只需使用条件聚合，无需子查询：

SELECT a.`Brand`, 
       SUM(`CONV` = 'Conv.') as ConvPgmGRPs,
       SUM(`CONV` = 'Spec.') as as SpecPgmGRPs,
       (SUM(`CONV` = 'Conv.') + SUM(`CONV` = 'Spec.')) AS 'Total PgmGRPs',
       ROUND(SUM(`CONV` = 'Conv.')/ (SUM(`CONV` = 'Conv.') + SUM(`CONV` = 'Spec.')),2) as ConvRatio,
       ROUND(SUM(`CONV` = 'Conv.')/ (SUM(`CONV` = 'Conv.') + SUM(`CONV` = 'Spec.')),2) as SpecRatio
FROM transform_data_1
GROUP BY `Brand`

---

我相信这就是你想要的：

select tab.`Date`
       , tab.brand
       , tab.market
       , Conv_PgmGRPs
       , Spec_PgmGRPs 
       , Total_PgmGRPs
       , ROUND(Conv_PgmGRPs / (Conv_PgmGRPs + Spec_PgmGRPs),2) as 'Conv. Ratio'
       , ROUND(Spec_PgmGRPs / (Conv_PgmGRPs + Spec_PgmGRPs),2) as 'Spec. Ratio'
from (select `Date`
       , brand
       , Market
       , (select sum(PgmGRPs)  
          from transform_data_1 t1 
          where t.`Date` = t1.`Date`
          and  t.brand = t1.brand
          and t.Market = t1.Market
          and t1.CONV = 'conv.') Conv_PgmGRPs
       , (select sum(PgmGRPs)  
          from transform_data_1 t1 
          where t.`Date` = t1.`Date`
          and  t.brand = t1.brand
          and t.Market = t1.Market
          and t1.CONV = 'Spec.') Spec_PgmGRPs
       , sum(PgmGRPs) Total_PgmGRPs
from transform_data_1 t
group by `Date`
       , brand
       , Market) tab

结果是：

---

使用条件聚合：

select date, brand, market,
  `Conv. PgmGRPs`, `Spec. PgmGRPs`, 
  `Conv. PgmGRPs` + `Spec. PgmGRPs` `Total PgmGRPs`,
  round(`Conv. PgmGRPs` / (`Conv. PgmGRPs` + `Spec. PgmGRPs`), 2)  `Conv. Ratio`,
  round(`Spec. PgmGRPs` / (`Conv. PgmGRPs` + `Spec. PgmGRPs`), 2)  `Spec. Ratio`
from (
  select date, brand, market, 
    sum(case when conv = 'conv.' then PgmGRPS end) `Conv. PgmGRPs`, 
    sum(case when conv = 'Spec.' then PgmGRPS end) `Spec. PgmGRPs`  
  from transform_data_1
  group by date, brand, market
) t

请参阅。
结果:

---

当您试图开发的查询变得太复杂时，使用暂存表就更容易了。您应该使用交叉表/透视表函数来创建要创建的交叉表

第一步。创建一个无任何计算/比率的交叉表暂存表。 第二步。运行sql语句来计算总数和比率

---

上面的查询类似于@forpas在上面编写的查询。

您应该缩进您的代码，这样更容易阅读hi@nicolas这是您请求的带有日期列的解决方案。希望没问题。干杯

| date       | brand | market | Conv. PgmGRPs | Spec. PgmGRPs | Total PgmGRPs | Conv. Ratio | Spec. Ratio |
| -----------| ----- | ------ | ------------- | ------------- | ------------- | ----------- | ----------- |
| 2020-01-01 | ABC   | MTL    | 80            | 20            | 100           | 0.8         | 0.2         |
| 2020-01-01 | ABC   | TO     | 70            | 40            | 110           | 0.64        | 0.36        |
| 2020-01-02 | DEF   | TO     | 80            | 20            | 100           | 0.8         | 0.2         |